Please explain.
OA is B
Absolute value of x
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One way for approaching absolute value problems is by looking at the geometric meaning.
|x-y| means distance between x and y on the number line. Always positive units.
|x| means distance between x and 0(origin) on number line
|y| means distance between y and 0(origin) on number line
The question is is the distance between x and y greater than the difference of distance between x and 0(origin) on number line and distance between y and 0(origin) on number line.
Stmt I
y < x
y=-4 x=4
|x-y| = 8
|x|= 4
|y| = 4
|x-y| > |x| - |y| yes
y=2 x=4
|x-y| = 2
|x|= 4
|y| = 2
|x-y| = |x| - |y| NO
insuff
Stmt II
xy<0
Either x is positive and y is negative or y is positive and x is negative
Take any value of x and y that satisfy either of the 2 conditions above u will notice that the distance between x and y (|x-y|) will always be greater than the difference of distance between x and 0(origin) on number line and distance between y and 0(origin) on number line.
SUFF
Choose B
Hope this helps and let me know if u still have questions.
Regards,
CR
|x-y| means distance between x and y on the number line. Always positive units.
|x| means distance between x and 0(origin) on number line
|y| means distance between y and 0(origin) on number line
The question is is the distance between x and y greater than the difference of distance between x and 0(origin) on number line and distance between y and 0(origin) on number line.
Stmt I
y < x
y=-4 x=4
|x-y| = 8
|x|= 4
|y| = 4
|x-y| > |x| - |y| yes
y=2 x=4
|x-y| = 2
|x|= 4
|y| = 2
|x-y| = |x| - |y| NO
insuff
Stmt II
xy<0
Either x is positive and y is negative or y is positive and x is negative
Take any value of x and y that satisfy either of the 2 conditions above u will notice that the distance between x and y (|x-y|) will always be greater than the difference of distance between x and 0(origin) on number line and distance between y and 0(origin) on number line.
SUFF
Choose B
Hope this helps and let me know if u still have questions.
Regards,
CR