MI3 wrote:Hello Mitch,
Thank you for coming back to me on this, but I am still not a 100% clear. A couple of my queries are mentioned below, if you may:
1. How do you identify that it is a weighted average/mixture problem?
2. Do we not need to consider other sects of population - i.e. those who aren't a transfer?
Here is the basic structure of a weighted average question:
Element 1 is X%.
Element 2 is Y%.
A mixture of Element 1 and Element 2 is Z%.
The DS question above is structured exactly this way:
The graduating men are 35% transfer.
The graduating women are 20% transfer.
When the men and women are combined, the resulting graduating class is 25% transfer.
Given the information above, we can determine the ratio of men to women in the graduating class.
One method is
alligation. Alligation is used to determine how much
weight must be given to each element in the mixture. Simply stated:
The proportion of each element in the mixture is the distance between the other two percentages.
Proportion of men = Class % - Women's % = 25-20 = 5.
Proportion of women = Men's % - Class % = 35-25 = 10.
The results above give us the ratio of men to women:
M:W = 5:10 = 1:2.
Since 1+2=3, the men are 1/3 = 33.34% of the class.
To illustrate:
Men = 100, Women = 200, Class = 300.
35% of the men are transfers = .35*100 = 35.
20% of the women are transfers = .2*200 = 40.
Total transfers = 35+40 = 75.
Total transfers/Total class = 75/300 = 25/100 = 25%.
As I noted in my original post, none of this math is needed in the DS question above. Given the info in the two statements, we have sufficient information to determine the ratio of men to women.
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