IF x & y are integers , is (x^2-y^2) divisible by 4
i. x-y is even
ii. x+y is even
D
Data Suff
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Hi,
(x^2-y^2) = (x+y)(x-y)
From(1): x-y is even.
So, x and y are both odd or both even.
In both cases x+y is even as well. So, (x+y).(x-y) is even*even = multiple of 4
Sufficient
From(2): x+y is even.
So, x and y are both odd or both even.
In both cases x-y is even as well. So, (x+y).(x-y) is even*even = multiple of 4
Sufficient
Hence, D
(x^2-y^2) = (x+y)(x-y)
From(1): x-y is even.
So, x and y are both odd or both even.
In both cases x+y is even as well. So, (x+y).(x-y) is even*even = multiple of 4
Sufficient
From(2): x+y is even.
So, x and y are both odd or both even.
In both cases x-y is even as well. So, (x+y).(x-y) is even*even = multiple of 4
Sufficient
Hence, D
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Statement 1: If (x - y) is even, then either x and y are both even or both odd.vinayreguri wrote:IF x & y are integers , is (x^2-y^2) divisible by 4
i. x-y is even
ii. x+y is even
In both the cases, (x + y) is also even.
Hence, (x² - y²) = (x - y)(x + y) = EVEN*EVEN = EVEN
Sufficient
Statement 2: If (x + y) is even, then either x and y are both even or both odd.
In both the cases, (x - y) is also even.
Hence, (x² - y²) = (x - y)(x + y) = EVEN*EVEN = EVEN
Sufficient
The correct answer is D.
Anurag Mairal, Ph.D., MBA
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