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by vineetbatra » Sat Nov 07, 2009 3:10 pm
if x < 0, then root(-x|x| ) is

-x
-1
1
x
root(x)

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by sanjana » Sun Nov 08, 2009 12:00 pm
IMO : -X
pick a number say x=-5
then,root(-x|x| ) = -(-5)|-5| = 5 = -x.

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by vineetbatra » Sun Nov 08, 2009 12:07 pm
How is it -X, the answer is 5 and not -5. Btw -x is the OA

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by sanjana » Sun Nov 08, 2009 9:09 pm
we took x as -5.The answer we got after substitution is 5 which is -(-5) = -(x).

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by vijay_venky » Sun Nov 08, 2009 11:02 pm
the definition for |x| goes as
|x|=-x when x<0
=x when x>0
This is the reason for the modulus of negative number to be positive.
Now -x|x|= -x*-x and this is (-x)2(square)
and sqrt((-x)2)=-x

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by vineetbatra » Mon Nov 09, 2009 9:48 am
Thanks a lot Sanjana and Venky, but I am still not able to comprehend the concept.

-x where x = -5 will be -(-5) = 5

|x| where x = -5 = |-5| = 5

root(5*5) = 5. I stop here, maybe I am missing a step or a concept.

Please let me know.

Thanks again,

Vineet

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by xcusemeplz2009 » Mon Nov 09, 2009 9:54 am
vineetbatra wrote:Thanks a lot Sanjana and Venky, but I am still not able to comprehend the concept.

-x where x = -5 will be -(-5) = 5

|x| where x = -5 = |-5| = 5

root(5*5) = 5. I stop here, maybe I am missing a step or a concept.

Please let me know.

till here u are correct now u have assume x=-5
and after solving u have got the value as 5 which is -(-5) or in other words -x

Thanks again,

Vineet
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by Stuart@KaplanGMAT » Mon Nov 09, 2009 10:00 am
vineetbatra wrote:Thanks a lot Sanjana and Venky, but I am still not able to comprehend the concept.

-x where x = -5 will be -(-5) = 5

|x| where x = -5 = |-5| = 5

root(5*5) = 5. I stop here, maybe I am missing a step or a concept.

Please let me know.

Thanks again,

Vineet
Everything you've done so far is fine, you just stopped before answering the question.

You chose x = -5.

You calculated the value of root(-x|x|) as + 5.

Now you need to actually think about how +5 relates to your chosen value of x; remember, when we pick numbers the last step is to plug the number we've chosen into the choices.

So, we plug x=-5 into the choices and see which one matches our result of +5:

-x ; -(-5) = +5... a match!

-1 ; not +5... eliminate.

1 ; not +5... eliminate.

x ; -5... not the same as +5... eliminate.

root(x) ; root(-5)... imaginary number, these don't show up on the GMAT (and certainly not the same as +5)... eliminate.

Only choice (A) gives us the answer "+5", therefore (A) is correct.
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by vineetbatra » Thu Nov 12, 2009 8:05 pm
Stuart,

Now I finally got it, I have to read the other side of the equation.

Thanks a lot.

Vineet