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muzali
- Senior | Next Rank: 100 Posts
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If x is not equal to -y, is [(x-y)/(x+y)]>1?
1. x>0
2. y<0
I tried the following approach:
[(x-y)/(x+y)]>1
so, x-y>x+y or, 2y<0, or y<0.
Alternatively, [(x-y)/(x+y)]>1, or [(x-y)/(x+y)]-1>0, or [-2y/(x+y)]>0, or -2y>0, or y<0
Thus I chose B, but the correct choice is E. Now knowing the answer, I tried substituting values for x and y and found E to be correct. What was incorrect in my previous approach(es) which led me to B?
Thanks.
1. x>0
2. y<0
I tried the following approach:
[(x-y)/(x+y)]>1
so, x-y>x+y or, 2y<0, or y<0.
Alternatively, [(x-y)/(x+y)]>1, or [(x-y)/(x+y)]-1>0, or [-2y/(x+y)]>0, or -2y>0, or y<0
Thus I chose B, but the correct choice is E. Now knowing the answer, I tried substituting values for x and y and found E to be correct. What was incorrect in my previous approach(es) which led me to B?
Thanks.













