A drives for (100 miles)/(Speed of A) = 100/40 hoursbobdylan wrote:A, B and C each drive 100-mile legs of a 300-mile course at speeds of 40, 50 and 60 miles per hour, respectively. What fraction of total time does A drive?
B drives for (100 miles)/(Speed of B) = 100/50 hours
C drives for (100 miles)/(Speed of C) = 100/60 hours
Hence, total time = (10/4 + 10/5 + 10/6) = 10(1/4 + 1/5 + 1/6) = 10(15/60 + 12/60 + 10/60) = (15 + 12 + 10)/6 = 37/6 hours
Hence, required fraction = (10/4)/(37/6) = (10*6)/(4*37) = (5*3)/37 = 15/37
The correct answer is C.
















