Tough work problem
This topic has expert replies
-
- Newbie | Next Rank: 10 Posts
- Posts: 6
- Joined: Thu Jul 19, 2007 9:14 am
Pumps A, B, and C operate at their respective constant rates. Pumps A and B, operating simultaneously, can fill a certain tank in 6/5 hours; pumps A and C, operating simultaneously, can fill a certain tank in 2/3 hours; and pumps B and C, operating simultaneously, can fill a certain tank in 6/5 hours. How many hours does it take A, B, and C, operating simultaneously, to fill the tank?
-
- Master | Next Rank: 500 Posts
- Posts: 103
- Joined: Wed May 30, 2007 6:17 am
- Followed by:1 members
This can be solved by breaking the given information to smaller pieces.
Like,
A+B = 5/6 (because, 1/6/5= 5/6)
A+C = 3/2
B+C = 5/6
Adding all the 3 equation gives,
2(A+B+C) = 5/6+3/2+5/6
2(A+B+C) = 19/6
A+B+C = 19/12
So time taken by 3 pumps can be written as 12/19
Like,
A+B = 5/6 (because, 1/6/5= 5/6)
A+C = 3/2
B+C = 5/6
Adding all the 3 equation gives,
2(A+B+C) = 5/6+3/2+5/6
2(A+B+C) = 19/6
A+B+C = 19/12
So time taken by 3 pumps can be written as 12/19