GMATPrep DS question

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GMATPrep DS question

by rcsrini » Sun Dec 04, 2011 4:58 pm
Following DS question is from GMATPrep.

Is |x| > |y| ?
1. x^2 > y^2
2. x > y

Can you please help with explaination ?

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by Anurag@Gurome » Sun Dec 04, 2011 10:25 pm
rcsrini wrote:Following DS question is from GMATPrep.

Is |x| > |y| ?
1. x^2 > y^2
2. x > y

Can you please help with explaination ?
(1) If x = -2, y = -1, then x² = 4, y² = 1. Here |x| > |y|. This will hold true for positive values of x and y.
It can be observed that |x| > |y| if x² > y²; SUFFICIENT.

(2)If x = 5, y = 3, then x > y and |x| > |y|
If x = -3, y = -4, then x > y but |x| < |y|
No definite answer; NOT sufficient.

The correct answer is A.
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by amit2k9 » Mon Dec 05, 2011 2:52 am
b for x|y = 3,2 & -1,-2. different results. eliminate.

a for x|y with same values as above |x|>|y| always.

hence A
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by rcsrini » Mon Dec 05, 2011 11:17 am
Thanks a lot ..