two ppl

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shibal: Master | Next Rank: 500 Posts; Posts: 345; Joined: Wed Mar 18, 2009 6:53 pm; Location: Sao Paulo-Brazil; Thanked: 12 times; GMAT Score:660

by shibal » Thu Jul 16, 2009 4:21 am

Two people walked the same distance, one person's speed is between 25 and 45,and if he used 4 hours, the speed of another people is between 45 and 60,and if he used 2 hours, how long is the distance?

don't have the OA sorry

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Source: Beat The GMAT — Problem Solving | Thu Jul 16, 2009 4:21 am

Bryant@VeritasPrep: MBA Admissions Consultant; Posts: 1090; Joined: Wed May 27, 2009 4:06 amFollowed by: 68 members; Thanked: 175 times; GMAT Score:750

by Bryant@VeritasPrep » Thu Jul 16, 2009 10:19 am

interesting question, as it seems indeterminable from the data given. You know that the speed of person one, or S1 times four hours will yield the distance and that S2 times two hours will yield the same distance, so S1 = 1/2 of S2. The only speeds that are possible then for S1, out of the choices are 25,26, 27, 28, 29 and 30, since doubling these speeds would yield a speed for S2 that is within guidelines (50-60). Problem is, these six number pairs all yield a workable, but different solution ranging in distances from 100 up to 120. so my answer would be d= between 100 and 120.

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tohellandback: Legendary Member; Posts: 752; Joined: Sun May 17, 2009 11:04 pm; Location: Tokyo; Thanked: 81 times; GMAT Score:680

Re: two ppl

by tohellandback » Thu Jul 16, 2009 3:33 pm

shibal wrote:Two people walked the same distance, one person's speed is between 25 and 45,and if he used 4 hours, the speed of another people is between 45 and 60,and if he used 2 hours, how long is the distance?

don't have the OA sorry

range for person1- 25*4=100 and 45*4=180. so 100<d<180
range for person 2-4582=90 and 60*2=120, so 90<d<120
common range is 100<d<120. that is the answer

The powers of two are bloody impolite!!

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rd85: Senior | Next Rank: 100 Posts; Posts: 39; Joined: Mon May 19, 2008 4:43 am

by rd85 » Fri Jul 17, 2009 6:07 am

S1, S2 Speed of person 1 and 2 resp.
t1, T2 Time taken by person 1 and 2 resp ie 4 and 2 hrs
D Distance

Since, D= ST
=> S1T1 = S2T2
=> S1/S2 = 1/2

From the range of S1 and S2 we can derive
S1,S2 to be
(25, 50) (26,52)....(30,60)

So distance would be
Min D=S2T = 50*2 =100
Max D= 60*2 = 120

so, 100<= D <=120

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