In a certain game, a large bag is filled with blue, green, purple and red chips worth 1, 5, x and 11 points each, respectively. The purple chips are worth more than the green chips, but less than the red chips. A certain number of chips are then selected from the bag. If the product of the point values of the selected chips is 88,000, how many purple chips were selected?
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Nice question.
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Factorize 88,000 as 11, 5^3 and 2^6. The purple chip has a value between 5 and 11 and you want an answer of the form n^m, where n is the value of the purple chip.
Split 2^6 in 2^3 and 2^3 you get two purple chips, each with a value of 8.
Split 2^6 in 2^3 and 2^3 you get two purple chips, each with a value of 8.
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everything was okay until you splite the 2^6 ... could you explain more please..kris610 wrote:Factorize 88,000 as 11, 5^3 and 2^6. The purple chip has a value between 5 and 11 and you want an answer of the form n^m, where n is the value of the purple chip.
Split 2^6 in 2^3 and 2^3 you get two purple chips, each with a value of 8.
Abdulla
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Think of it like this. We have 2^6 = 64Abdulla wrote:everything was okay until you splite the 2^6 ... could you explain more please..kris610 wrote:Factorize 88,000 as 11, 5^3 and 2^6. The purple chip has a value between 5 and 11 and you want an answer of the form n^m, where n is the value of the purple chip.
Split 2^6 in 2^3 and 2^3 you get two purple chips, each with a value of 8.
Possible value of chips:
If the chip had a value of 64 only 1 would be selected.
If the chip had a value of 8 then 2 would be selected (8x8)
If the chip value of 4 then 3 would be selected (4x4x4)
If the chip value was 2 then 6 would be selected. (2x2x2x2x2x2)
We know from the problem that the chip value must be between 5 and 11 so the value of the chip must be 8. Therefore, 2 purple chips were selected.
Hope this helps
Hi Abdulla,
Let me try to make it clearer.
You have 2^6, which you need to express as a power of 6,7,8,9 or 10.
Now, 6 and 9 are ruled out as you do not have 3 in the factors and likewise for 7.
If you want to express a power of 10, you need to use one or more of the 5s (from 5^3), in which case the remaining 2s cannot be expressed as a power of 8 or 10 -- you can try this out.
So, you are left with the option of splitting 2^6 into two 2^3s i.e. you have two 8s for the two purple chips.
Let me try to make it clearer.
You have 2^6, which you need to express as a power of 6,7,8,9 or 10.
Now, 6 and 9 are ruled out as you do not have 3 in the factors and likewise for 7.
If you want to express a power of 10, you need to use one or more of the 5s (from 5^3), in which case the remaining 2s cannot be expressed as a power of 8 or 10 -- you can try this out.
So, you are left with the option of splitting 2^6 into two 2^3s i.e. you have two 8s for the two purple chips.
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Think of it like this. We have 2^6 = 64
Possible value of chips:
If the chip had a value of 64 only 1 would be selected.
If the chip had a value of 8 then 2 would be selected (8x8)
If the chip value of 4 then 3 would be selected (4x4x4)
If the chip value was 2 then 6 would be selected. (2x2x2x2x2x2)
We know from the problem that the chip value must be between 5 and 11 so the value of the chip must be 8. Therefore, 2 purple chips were selected.
Very good explanation Dmateer!
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very well done!kris610 wrote:Factorize 88,000 as 11, 5^3 and 2^6. The purple chip has a value between 5 and 11 and you want an answer of the form n^m, where n is the value of the purple chip.
Split 2^6 in 2^3 and 2^3 you get two purple chips, each with a value of 8.
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