5-Day Free Trial
5-day free, full-access trial TTP
Available with Beat the GMAT members only code
MORE DETAILS
Crazy problem solving question..
This topic has expert replies
they are asking for bread only buyers which equals neiter( C or M) buyers which equals 1-probability of M&C ONLY buyers.
C only = 50-20 =30
M only = 40-20 =20
then P (M&C) = 20+30/100 or 1/2
1-1/2 =1/2 probability of M only.
C only = 50-20 =30
M only = 40-20 =20
then P (M&C) = 20+30/100 or 1/2
1-1/2 =1/2 probability of M only.
Thanks for answereing, but the correct answer is 3/10 not 1/2. thanks again.. someone else please help me..freedsl wrote:they are asking for bread only buyers which equals neiter( C or M) buyers which equals 1-probability of M&C ONLY buyers.
C only = 50-20 =30
M only = 40-20 =20
then P (M&C) = 20+30/100 or 1/2
1-1/2 =1/2 probability of M only.
What i did wrong was take 20 off twice, anyway
So you have the formula ALL buyers that trade in M and C (Unique buyers) = M+C- both (M&C) = 50+40-20 =70 the prob for this is 70/100 or 7/10
the opossite which would be only B buyers is 1- 7/10 =3/10
So you have the formula ALL buyers that trade in M and C (Unique buyers) = M+C- both (M&C) = 50+40-20 =70 the prob for this is 70/100 or 7/10
the opossite which would be only B buyers is 1- 7/10 =3/10
-
Stuart@KaplanGMAT
- GMAT Instructor
- Posts: 3225
- Joined: Tue Jan 08, 2008 2:40 pm
- Location: Toronto
- Thanked: 1710 times
- Followed by:614 members
- GMAT Score:800
Kaching!jscoligan wrote:Cake+muffin+neither-both=Real total
50+40+neither-20=100
neither=30
30/100=> 3/10
Perfect question for the overlapping sets formula:
True # of items = # with characteristic 1 + # with char 2 + # with neither char - # with both chars
In this case:
100 = 50 + 40 + neither - 20
100 = 70 + neither
30 = neither
So, probability of finding a "neither" person is 30/100 = 3/10
Stuart Kovinsky | Kaplan GMAT Faculty | Toronto
Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course
