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word problem

by sud21 » Thu Jan 19, 2012 11:01 pm
On the first day, a company sells orange beverage mixed with the same amount of orange juice and water. On the next day, the company adds the water twice as much as the amount of orange juice sold on the first day. If the company sells a glass of the beverage at $0.6 on the first day, how much is the price on the next day if the company get the same revenue?
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by sanju09 » Fri Jan 20, 2012 2:27 am
sud21 wrote:On the first day, a company sells orange beverage mixed with the same amount of orange juice and water. On the next day, the company adds the water twice as much as the amount of orange juice sold on the first day. If the company sells a glass of the beverage at $0.6 on the first day, how much is the price on the next day if the company get the same revenue?
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by shankar.ashwin » Fri Jan 20, 2012 4:29 am
Assuming water is *free* of cost,

lets assume on Day 1 the beverage comprises of 500ml water and 500ml orange juice - - total 1 litre for $0.6

Now on day 2, water = twice the amount of orange juice, therefore 1000ml of water and 500 ml of orange juice = 1.5 litre for $0.6.

Since its sold for the same revenue (cost of 1.5 ltr dilute juice = cost of 1 ltr concentrated juice)

Price of dilute juice/ltr (day 2) = 0.6/1.5 = $0.4 IMO
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