are integers x, y and z consecutive?
1) y equals the arithmetic mean of x and z
2) x = -z
[spoiler]OA's E, but I opted for A[/spoiler]
consecutive integers?
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- thephoenix
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S1) 2,4,6 Y IS MEAN BUT X,Y,Z ARE NOT CONSECUTIVE
1,2,3 Y IS MEAN AND X,Y,Z ARE CONSECUTIVE
INSUFF
S2) INSUFF
1,2,3 Y IS MEAN AND X,Y,Z ARE CONSECUTIVE
INSUFF
S2) INSUFF
- sars72
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Rahul, i think the mistake you may be making is that you are consider something like 1,3,5 to be consecutive integers when they are not... silly mistake, which I have made on occassion. If not, then here is the explanation to help you out:
1,2,3 -> 2(1+3)/2 --> consecutive
Therefore, since we both yes & no, the statement by itself is insufficient -> Choices A & D are eliminated
combining 1 & 2 ->
-1,0,1 -> 0= (-1+1)/2 && -1 = -(1) -->consecutive
-2,0,2 -> 0= (-2+2)/2 && -2=(-2) --> not consecutive
Therefore the two statements combined are also insufficient, and thus E is the correct answer.
are integers x, y and z consecutive?
2,4,6 -> 4=(2+6)/2 --> not consecutive1) y equals the arithmetic mean of x and z
1,2,3 -> 2(1+3)/2 --> consecutive
Therefore, since we both yes & no, the statement by itself is insufficient -> Choices A & D are eliminated
we have nothing about y, so by itself the statement is insufficient -> B is eliminated2) x = -z
combining 1 & 2 ->
-1,0,1 -> 0= (-1+1)/2 && -1 = -(1) -->consecutive
-2,0,2 -> 0= (-2+2)/2 && -2=(-2) --> not consecutive
Therefore the two statements combined are also insufficient, and thus E is the correct answer.