Problem Solving

There is a square field with three cows tethered at three different corners of the field. The ropes, used to tether the cows, are all of length 14√2. If the area of the square field is 784 m2, what is the area of the field that cannot be accessed by any of the three cows? (assume π = 22/7)

1. 184 sq.m

2.168 sq.m

3.161 sq.m

4.322 sq.m

5.84 sq.m

side of the square = sqroot 784 = 28

3 cows tethered at 3 corners of the circle make 3 parts of the entire circle with diameter of 28 or radius of 14

area of the square tethered by 3 cows = 3(pi*r^2)/4 = [3*(22)*14^2]/(7*4)

= 3*11*14 = 462

area not accessed by any of the cows = area of square - 462 = 784 -462 = 322


OA?

OA is 84

winnerhere wrote:There is a square field with three cows tethered at three different corners of the field. The ropes, used to tether the cows, are all of length If the area of the square field is 784 m2, what is the area of the field that cannot be accessed by any of the three cows? (assume π = 22/7)

1. 184 sq.m

2.168 sq.m

3.161 sq.m

4.322 sq.m

5.84 sq.m

missed something there??

oops..sorry..the length is 14√2.

now the post is rightly edited.

please check the image..the area in black is the area we need to find.
The other half of the square is grazed completely by the cows.
half of the area of square=784//2=392
area of each reason A and B is pi * (14√2)^2/8

so area of regions A and B=2* 22/7 * 2* 14 *14 * 1/8= 308

Area of the black region=392-308=84

Thank u so much buddy!