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by atlantic » Tue Jun 17, 2008 8:42 am
(1001^2-999^2)/(101^2-99^2)=?

Any algebric approach?
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by durgesh79 » Tue Jun 17, 2008 8:55 am
There is a formula in algebra

A^2 - B^2 = (A+B)*(A-B)

try using this in this question. :)
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by atlantic » Tue Jun 17, 2008 9:15 am
Many thanks durgesh, really appreciate it.
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by Motherjane » Tue Jun 17, 2008 9:42 am
Using the formula Durgesh used,

the problem reduces to : (2000 * 2)/(200*2) = 10

The answer is 10.
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