Two oil cans, X and Y, are right
circular cylinders, and the height and
the radius of Y are each twice those of
X. If the oil in can X, which is filled to
capacity, sells for $2, then at the same
rate, how much does the oil in can Y
sell for if Y is filled to only half its
capacity?
(A) $1
(B) $2
(C) $3
(D) $4
(E) $8
OA is E
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cylinders
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das.ashmita
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Cylinder X : radius-r height-h volume-pi*r^2*h
Cylinder Y : radius-2r height-2h volume-pi*(2r)^2*(2h) = 8*pi*r^2*h
Since Y is half filled .... volume of it's content = 4*pi*r^2*h = 4*(volume of X)
Price of total volume of X = $2
Price of half volume of Y = $2 * 4 = $8
Ans E
Cylinder Y : radius-2r height-2h volume-pi*(2r)^2*(2h) = 8*pi*r^2*h
Since Y is half filled .... volume of it's content = 4*pi*r^2*h = 4*(volume of X)
Price of total volume of X = $2
Price of half volume of Y = $2 * 4 = $8
Ans E
