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please help . . . question thanks

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Senior | Next Rank: 100 Posts
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please help . . . question thanks

by silvia928 » Sun May 25, 2008 11:06 pm
1.) When positive integer x is divided by positive integer y, the remainder is 9. If x/y=96.12, what is the value of y?

A.96
B.75
C.48
D.25
E.12

The answer is: B (75)
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by ksh » Sun May 25, 2008 11:14 pm
Hi Silvia,

here is how..

x/y has a remainder of 9
also x/y=96.12
so y=9/0.12=75

hope it's ok.
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by silvia928 » Sun May 25, 2008 11:20 pm
wow thanks!!
you are so smart. ..
i didn't even think of tha
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by Luca80 » Sun May 25, 2008 11:34 pm
don't get it...
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by Luca80 » Sun May 25, 2008 11:39 pm
don't get it...
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by getneonow » Mon May 26, 2008 12:31 am
Luca80 wrote:don't get it...
x = 96.12y = ky + 9

=> 96y + 0.12 y = ky + 9

=> k = 96 and 0.12 y = 9

=> y = 9/0.12 = 75

Hope its clear now

Neo
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