Please help with the question.. Please explain the answer...
The annual rent collected by a corporation from a certain building was x percent more in 1998 than in 1997 and y percent less in 1999 than in 1998. Was the annual rent collected by the corporation from the building more in 1999 than in 1997?
(1) x > y
(2) xy/100 < x – y
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
OA after some discussion...
Rent Collected
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- cubicle_bound_misfit
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This is how I tried,
Let's say
1997 -----> rent collected 100 $
1998 ----------> rent collected ( 100 +x )$
1999 ---------> (100+x) - (100+x)*y/100
==> 100 + (x-y) - xy/100
so if we can prove (x-y) - xy/100 > 0 we are done.
only thing we know is that x, y >0 hence xy/100 but x-y can be <0 and - xy/100 is definitely < 0
stmt 1. x>y hence x-y >0 but if xy/100 >x-y then expression is negative if xy/100 < x-y then expression is +ve. insufficient
stmt 2: xy/100 < (x-y) hence (x-y) - xy/100 >0 SUFFICIENT IMO it is B.
What is OA??
regards,
CBM
Let's say
1997 -----> rent collected 100 $
1998 ----------> rent collected ( 100 +x )$
1999 ---------> (100+x) - (100+x)*y/100
==> 100 + (x-y) - xy/100
so if we can prove (x-y) - xy/100 > 0 we are done.
only thing we know is that x, y >0 hence xy/100 but x-y can be <0 and - xy/100 is definitely < 0
stmt 1. x>y hence x-y >0 but if xy/100 >x-y then expression is negative if xy/100 < x-y then expression is +ve. insufficient
stmt 2: xy/100 < (x-y) hence (x-y) - xy/100 >0 SUFFICIENT IMO it is B.
What is OA??
regards,
CBM
Cubicle Bound Misfit
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IMO D
Both are correct
this value can be greater than 0 only when x>y
You can plug in any positive value of x and y and check,if this relation holds true,
then (x-y) - xy/100> 0
And why I say positive value of x and y because we cannot have percent values in negative
Hope this Helps
Karan
Both are correct
(x-y) - xy/1001999 ---------> (100+x) - (100+x)*y/100
==> 100 + (x-y) - xy/100
this value can be greater than 0 only when x>y
You can plug in any positive value of x and y and check,if this relation holds true,
then (x-y) - xy/100> 0
And why I say positive value of x and y because we cannot have percent values in negative
Hope this Helps
Karan
- cubicle_bound_misfit
- Master | Next Rank: 500 Posts
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