If mv<pv<0, is v>0?
St1: m<p
St2: m<0
DS.... GMATPrep Prac Test 2
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Hi,
Option 1 is sufficient to answer the question.
pv< 0. hence, either p <0 or v < 0.
It is given that p > m.
So pv > mv can only be true when v has a +ve sign. If v is -ve, then p < m.
hence, because p > m is given and that pv >mv, v > 0.
From this it follows that p < 0 which is stated in Option 2, which isn't required. It can be deduced.
Option 1 is sufficient to answer the question.
pv< 0. hence, either p <0 or v < 0.
It is given that p > m.
So pv > mv can only be true when v has a +ve sign. If v is -ve, then p < m.
hence, because p > m is given and that pv >mv, v > 0.
From this it follows that p < 0 which is stated in Option 2, which isn't required. It can be deduced.
Sandy
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Hello Bharatishiv,bharatishiv wrote:If mv<pv<0, is v>0?
St1: m<p
St2: m<0
We know that mv<pv from the start. Since statement 1 tells us that m<p, it means that dividing both sides of mv<pv by v did not flip the direction of the inequality, so v must be positive. That answers the question.
We know from the start that mv<0, which means m and v have opposite signs. Since Statement 2 tells us that m is negative, it must be the case that v is positive. That answers the question.
The answer is D
A more detailed solution as well as a step-by-step video solution is available at GMATPrep Question 1241. To practice similar questions in timed drills, set topic='Number Properties' and difficulty='600-700' in the Drill Generator.
Good luck
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