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shankar.ashwin
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Given T/S = 3/80
Now we got to find S, when T = 5.
Corresponding S = (80/3)*5 = 133.3
S cannot be a decimal, hence D
Now we got to find S, when T = 5.
Corresponding S = (80/3)*5 = 133.3
S cannot be a decimal, hence D
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sl750
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The question says T/S > 3/80, and not T/S=3/80; S<133shankar.ashwin wrote:Given T/S = 3/80
Now we got to find S, when T = 5.
Corresponding S = (80/3)*5 = 133.3
S cannot be a decimal, hence D
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shankar.ashwin
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Technically we have 5/x > 3/80sl750 wrote: The question says T/S > 3/80, and not T/S=3/80; S<133
or 400 >3S and S<133.33, which is 133.
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abhi0697
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Kindly check out the below link for video solution:garima99 wrote:attached
https://www.youtube.com/watch?v=7tSwzFL1jkA
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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HeyArnold
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What's the doubt?
if the ratio must be larger than 3 / 80
And there are 5 TA's, then first:
3 / 80 = 5 / x
x = 400/3 = 133.3
So the ratio must be larger than 5 / 133.3
You can't have 0.3 students, so you can have 133 students and still have a larger ratio than 5 / 133.3
if the ratio must be larger than 3 / 80
And there are 5 TA's, then first:
3 / 80 = 5 / x
x = 400/3 = 133.3
So the ratio must be larger than 5 / 133.3
You can't have 0.3 students, so you can have 133 students and still have a larger ratio than 5 / 133.3
