K is a rectangular solid. Find the volume of K
(1) a diagonal line across the front face of K has a length of 40
(2) a diagonal line across the bottom face of K has a length of 25
OA E
Source: Magoosh
K is a rectangular solid. Find the volume of K
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Say, the length, width and height of K are a, b, and c, respectively.BTGmoderatorDC wrote:K is a rectangular solid. Find the volume of K
(1) a diagonal line across the front face of K has a length of 40
(2) a diagonal line across the bottom face of K has a length of 25
OA E
Source: Magoosh
Thus, volume of K = abc
Let's take each statement one by one.
(1) A diagonal line across the front face of K has a length of 40.
=> a^2 + b^2 = 1600. No information about c. Insufficient.
(2) A diagonal line across the bottom face of K has a length of 25.
Say a is the common side.
=> a^2 + c^2 = 625. No information about c. Insufficient.
(1) and (2) together
We have
a^2 + b^2 = 1600 and
a^2 + c^2 = 625
Two equations and three variable -- can't get the unique values of a, b and c. insufficient.
The correct answer: E
Hope this helps!
-Jay
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You can easily test values to prove insufficiency.BTGmoderatorDC wrote:K is a rectangular solid. Find the volume of K
(1) a diagonal line across the front face of K has a length of 40
(2) a diagonal line across the bottom face of K has a length of 25
OA E
Source: Magoosh
(1) a diagonal line across the front face of K has a length of 40
This give us limited information about 2 of our dimensions, but nothing about the 3rd. It's easy to imagine 40 as the hypotenuse of a 3 : 4 : 5 triangle, so we can imagine side lengths of 24 and 32. But what's the other dimension? It could be 1, or it could be 100, etc. This doesn't tell us about volume.
(2) a diagonal line across the bottom face of K has a length of 25
We can apply the same logic as with (1). Knowing 1 diagonal gives limited information about 2 of the 3 dimensions, but nothing about the 3rd. Insufficient.
(1) & (2) Together
With statement 1, we could easily imagine nice, clean integers. For this one, we can't quite as easily off the tops of our heads. But... we know that 25^2 = 625, and you might know that 24^2 = 576. The difference is 49, so it turns out that a 7: 24 : 25 is an all-integer right triangle. (Even if you didn't know these exact values, you could picture a triangle with one side length of 24 and a diagonal of 25, so another side length that's quite a bit shorter than 24).
The dimensions of this rectangular solid would be 32*24*7.
We could also imagine a version with a perfectly square bottom face, with side lengths of 25/(sqrt(2)), or approximately 18.
We don't need to calculate the other dimensions - we can see that the more cube-like it is, the greater its volume would be.
By contrast, imagine stretching it out so the depth is negligible, and the bottom length is almost 25. We could have a diagonal of 25 with hardly any depth at all, and a short-but-long front face with a diagonal of 40. Clearly the less regular (the less cube-like) we get, the smaller the volume becomes.
This is insufficient. The answer is E.
Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education
EdM in Mind, Brain, and Education
Harvard Graduate School of Education