If the two-digit integers M and N are positive and have the same digits, but in reverse order, which of the following CANNOT be the sum of M and N?
A) 181
B) 165
C) 121
D) 99
E) 44
The explanation made this problem more confusing than it originally was.
Help plz.
OA is A
Integer confusion
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A 2 digit integer can be written in the following way: 10a+b; where a is the 10ths digit and b the units digit.
For instance: 21 = 10*2 + 1
So let M = 10a+b
and N = 10b+a (reverse the 10ths and units digit of M).
M+N = 11a+11b
= 11(a+b)
Hence the sum of M and N should be divisible by 11.
Only A doesn't fit the bill.
For instance: 21 = 10*2 + 1
So let M = 10a+b
and N = 10b+a (reverse the 10ths and units digit of M).
M+N = 11a+11b
= 11(a+b)
Hence the sum of M and N should be divisible by 11.
Only A doesn't fit the bill.