Data Sufficiency

In 1995 Division A of Company X had 4 850 customers. if there were 86 service errors in Division A that year, what was the service-error rate, in number of service errors per 100 customers, for Division B of company X in 1995 ?

(1) In 1995, the overall service-error rate for Divisions A and B combined was 1.5 service errors per 100 customers

(2) In 1995 Division B had 9350 customers, none of whom were customers of Division A


From Statement (1)

(86 + x ) / (4850 + B) = 1.5 / 100

Where x = errors in Division B, B = customers in B.

Not Sufficient.

Is the above equation right?


From Statement (2)

We get B. Not Sufficient.


(1) + (2)

x is the only unknown. We can find x and later service errors per 100 customers.

IMO C

1st stmt we don't have b's customers...

2nd we don't have the errors made by div b.

combined we can find it....

IMO B

we have

85+Errors in B = 1.5/100*((4 850+9350))

thus ans is errors in B/9350

nervesofsteel wrote:IMO B

we have

85+Errors in B = 1.5/100*((4 850+9350))

thus ans is errors in B/9350

You don't know about 1.5 in B.
So it has to be C

rajanyadav wrote:

nervesofsteel wrote:IMO B

we have

85+Errors in B = 1.5/100*((4 850+9350))

thus ans is errors in B/9350

You don't know about 1.5 in B.
So it has to be C

Sorry I used both 1) and 2) and still marked the ans as B..

MY bad.... ans should be C...

C should be the answer..

IMO-A

What is the OA?
the service-error rate, in number of service errors per 100 customers :
For "A"

(86/4850)*100
Now let the error rate for "B" be x

thus,

(86/4650)*100 + x = 1.5

Clearly we can calculate x

so A

OA (C) [lachka labak]

A can't be the answer because we do not know if any customers overlap in St 1

My equation would be:

1.5% = (86+x)/(4850+y) * 100

stmt # 1: Supplies 1.5% in the above eqn.
stmt # 2: Supplies y in the above eqn.

Together, we will be able to find x. Thus C is the answer.