A man buys shares at a discount of Rs.x. Later he sells all but 10 of the shares he purchased at a
premium of Rs.x. If his investment was Rs.4500 and proceeds from the sale were Rs.6250, how
many shares did he buy originally ? [Assume face value of shares as Rs.100.]
1] 50 2] 40 3] 60 4] 90
discounts
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Man buys N the shares at Rs. (100 - x) per share and invests a total of Rs. 4,500.
This gives us the equation : 100 - x = 4500/N
=> x = 100*(N - 45) / N
He sells all but 10, i.e. (N - 10) shares at a price of (100 + x) per share.
The net proceeds would be: (N - 10) * (100 + x) = 6250
Substituting for x: [N - 10] * (100 + 100*(N-45)/N) = 6250
=> (N-10) * (200N - 4500) = 6250N
=> 200N^2 - 6500N + 45000 = 6250N
=> 200N^2 - 12750N + 45000 = 0
=> 4N^2 - 255N + 900 = 0
=> N = 60 or N = 3.75
Since N must be an integer, the answer is 60.
This gives us the equation : 100 - x = 4500/N
=> x = 100*(N - 45) / N
He sells all but 10, i.e. (N - 10) shares at a price of (100 + x) per share.
The net proceeds would be: (N - 10) * (100 + x) = 6250
Substituting for x: [N - 10] * (100 + 100*(N-45)/N) = 6250
=> (N-10) * (200N - 4500) = 6250N
=> 200N^2 - 6500N + 45000 = 6250N
=> 200N^2 - 12750N + 45000 = 0
=> 4N^2 - 255N + 900 = 0
=> N = 60 or N = 3.75
Since N must be an integer, the answer is 60.
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No of shares bought = 10y
Each share is bought at 100 - x = 4500/10y = 450/y ---(1)
Selling price of each share is 100+x = 6250/10y-10 = 625/(y-1) --------(2)
Adding 1 and 2
200 = 450/y + 625/(y-1)
Answer option are 50,40,60 and 90
so possible values of y are 5, 4,6,9 and correspondingly (y-1) = 4,3,5,9
625 cannot be divided by 4 even no , 3 ( sum of the digits - 6+2+5 = 13 is not a multiple of 3) or 9 ( sum of the digits are not a multiple of 9)
IMO 60
Each share is bought at 100 - x = 4500/10y = 450/y ---(1)
Selling price of each share is 100+x = 6250/10y-10 = 625/(y-1) --------(2)
Adding 1 and 2
200 = 450/y + 625/(y-1)
Answer option are 50,40,60 and 90
so possible values of y are 5, 4,6,9 and correspondingly (y-1) = 4,3,5,9
625 cannot be divided by 4 even no , 3 ( sum of the digits - 6+2+5 = 13 is not a multiple of 3) or 9 ( sum of the digits are not a multiple of 9)
IMO 60