Train A left station T at 3:30 p.m. and traveled on straight tracks at a constant speed of 60 miles per hour. Train B left station T on adjacent straight tracks in the same direction that train A traveled on. Train B left station T 40 minutes after train A, and traveled at a constant speed of 75 miles per hour. Train B overtook train A on these straight tracks. At what time did train B overtake train A?
4:10
5:40
6:10
6:50
7:30
speed distance time question
This topic has expert replies
-
- Senior | Next Rank: 100 Posts
- Posts: 44
- Joined: Tue Mar 05, 2013 10:18 pm
- Thanked: 4 times
- ganeshrkamath
- Master | Next Rank: 500 Posts
- Posts: 283
- Joined: Sun Jun 23, 2013 11:56 pm
- Location: Bangalore, India
- Thanked: 97 times
- Followed by:26 members
- GMAT Score:750
Speed of train A = 60 mphrishianand7 wrote:Train A left station T at 3:30 p.m. and traveled on straight tracks at a constant speed of 60 miles per hour. Train B left station T on adjacent straight tracks in the same direction that train A traveled on. Train B left station T 40 minutes after train A, and traveled at a constant speed of 75 miles per hour. Train B overtook train A on these straight tracks. At what time did train B overtake train A?
4:10
5:40
6:10
6:50
7:30
Train B leaves after 40 minutes.
Distance between the two trains at this time = speed * time = 60*(40/60) = 40 miles
Time taken for the two trains to meet after train B starts
= distance/(relative speed)
= 40/(75-60)
= 40/15 hours
= 40/15*60 minutes = 160 minutes
Train A left 40 minutes before B started.
So, train B meets train A (160+40) = 200 minutes after train A leaves.
3.30pm + 200 minutes = 6.50pm
Choose D
Cheers
Every job is a self-portrait of the person who did it. Autograph your work with excellence.
Kelley School of Business (Class of 2016)
GMAT Score: 750 V40 Q51 AWA 5 IR 8
https://www.beatthegmat.com/first-attemp ... tml#688494
Kelley School of Business (Class of 2016)
GMAT Score: 750 V40 Q51 AWA 5 IR 8
https://www.beatthegmat.com/first-attemp ... tml#688494
GMAT/MBA Expert
- Brent@GMATPrepNow
- GMAT Instructor
- Posts: 16207
- Joined: Mon Dec 08, 2008 6:26 pm
- Location: Vancouver, BC
- Thanked: 5254 times
- Followed by:1268 members
- GMAT Score:770
Here's one approach.rishianand7 wrote:Train A left station T at 3:30 p.m. and traveled on straight tracks at a constant speed of 60 miles per hour. Train B left station T on adjacent straight tracks in the same direction that train A traveled on. Train B left station T 40 minutes after train A, and traveled at a constant speed of 75 miles per hour. Train B overtook train A on these straight tracks. At what time did train B overtake train A?
4:10
5:40
6:10
6:50
7:30
Train A had a 40-minute head start (i.e., 2/3 of an hour head start).
Distance = (time)(speed)
So, head start distance = (2/3)(60) = 40-mile head start.
At 4:10, train B leaves the station, traveling at 75 mph
Train A is traveling at 60 mph
IMPORTANT: The 15mph difference in their speeds (75 - 60 = 150) means that, for EVERY HOUR, the distance between the trains shrinks by 15 MILES. In other words, we might say that the "speed of shrinkage" = 15 mph.
So, how long will it take to shrinks the initial 40-mile distance between them?
Time = distance/speed
So, time = 40/15 = 8/3 = 2 2/3 hours = 2 hours 40 minutes
The time when train B overtakes A = 4:10 + (2 hours 40 minutes) [spoiler]= 6:50 = D[/spoiler]
Cheers,
Brent
GMAT/MBA Expert
- Brent@GMATPrepNow
- GMAT Instructor
- Posts: 16207
- Joined: Mon Dec 08, 2008 6:26 pm
- Location: Vancouver, BC
- Thanked: 5254 times
- Followed by:1268 members
- GMAT Score:770
Another approach is to begin with a "word equation".rishianand7 wrote:Train A left station T at 3:30 p.m. and traveled on straight tracks at a constant speed of 60 miles per hour. Train B left station T on adjacent straight tracks in the same direction that train A traveled on. Train B left station T 40 minutes after train A, and traveled at a constant speed of 75 miles per hour. Train B overtook train A on these straight tracks. At what time did train B overtake train A?
4:10
5:40
6:10
6:50
7:30
When train B overtakes train A, we know that they have both traveled the same (equal) distance.
So, we can write: Train A's travel distance = Train B's travel distance
Distance = (speed)(time)
We know the speeds of the trains, but what about the times?
IMPORTANT: Let's base travel times from the time train B left the station
So, when train B overtakes train A we can say:
Train B's travel time = t hours
Train A's travel time = t + 2/3 hours (since train A had already traveled for 40 minutes before train B left the station)
Okay, we're ready to transform the word equation into an equation:
Train A's travel distance = Train B's travel distance
(60)(t + 2/3 hours) = (75)(t)
60t + 40 = 75t
40 = 15t
t = 40/15 = 8/3 = 2 2/3 hours.
Since we based the travel times from the time train B left the station (4:10), the time when train B overtakes A = 4:10 + (2 2/3 hours)[spoiler] = 6:50 = D [/spoiler]
Cheers,
Brent
Last edited by Brent@GMATPrepNow on Thu Aug 29, 2013 6:44 am, edited 1 time in total.
GMAT/MBA Expert
- Brent@GMATPrepNow
- GMAT Instructor
- Posts: 16207
- Joined: Mon Dec 08, 2008 6:26 pm
- Location: Vancouver, BC
- Thanked: 5254 times
- Followed by:1268 members
- GMAT Score:770
IMPORTANT: In my approach (using a "word equation"), I based both travel times from the time train B left the station. I want to point out that I don't necessarily have to do this in order to solve the question. Instead I could have based the travel times from the time train A left the station. My answer will still be the same.rishianand7 wrote:Train A left station T at 3:30 p.m. and traveled on straight tracks at a constant speed of 60 miles per hour. Train B left station T on adjacent straight tracks in the same direction that train A traveled on. Train B left station T 40 minutes after train A, and traveled at a constant speed of 75 miles per hour. Train B overtook train A on these straight tracks. At what time did train B overtake train A?
4:10
5:40
6:10
6:50
7:30
I'll show you.
When train B overtakes train A, we know that they have both traveled the same (equal) distance.
So, we can write: Train A's travel distance = Train B's travel distance
Train A's travel time = t hours
Train B's travel time = t - 2/3 hours (since train B did not travel for the first 40 minutes after train A left the station)
Okay, we're ready to transform the word equation into an equation:
Train A's travel distance = Train B's travel distance
(60)(t) = (75)(t - 2/3)
60t = 75t - 50
50 = 15t
t = 50/15 = 10/3 = 3 1/3 hours.
Since we based the travel times from the time train A left the station (3:30), the time when train B overtakes A = 3:30 + (3 1/3 hours)[spoiler] = 6:50 = D [/spoiler]
Cheers,
Brent
- GMATGuruNY
- GMAT Instructor
- Posts: 15539
- Joined: Tue May 25, 2010 12:04 pm
- Location: New York, NY
- Thanked: 13060 times
- Followed by:1906 members
- GMAT Score:790
A's rate = 60mph, B's rate = 75mph.rishianand7 wrote:Train A left station T at 3:30 p.m. and traveled on straight tracks at a constant speed of 60 miles per hour. Train B left station T on adjacent straight tracks in the same direction that train A traveled on. Train B left station T 40 minutes after train A, and traveled at a constant speed of 75 miles per hour. Train B overtook train A on these straight tracks. At what time did train B overtake train A?
4:10
5:40
6:10
6:50
7:30
In the 40 minutes from 3:30pm to 4:10pm, the distance traveled by A = r*t = 60 * 2/3 = 40 miles.
Every hour thereafter, A travels 60 more miles, while B travels 75 miles.
At 5:10pm, A = 40+60 = 100 miles, B = 75 miles.
At 6:10pm, A = 100+60 = 160 miles, B = 75+75 = 150 miles.
At 7:10pm, A = 160+60 = 220 miles, B = 150+75 = 225 miles.
Since B is 5 miles ahead at 7:10pm, B must have overtaken A between 6:10pm and 7:10pm.
The correct answer is D.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
- DamianDavila
- Newbie | Next Rank: 10 Posts
- Posts: 4
- Joined: Thu Nov 21, 2013 4:47 pm
- Location: Honolulu, HI
Here is my approach:
B leaves later than A so it first needs to catch up to A, and because it is going faster than A, B will eventually overtake A.
At 4:10 pm, A has covered 2/3 of what it would cover in 1 hour (40/60 minutes), so 60 x 2/3 = 40 miles.
Let's do a table of the trains after every hour:
[Time lapsed] [A]
[0 hours] [40] [0]
[1 hour] [100] [75]
[2 hours] [160] [150]
[3 hours] [220] [225]
As you can see, B is already 5 miles ahead of A after 3 hours, so that means that B overtakes A a couple minutes before 3 hours have passed. The closest answer choice is [spoiler](D) 2 hours 40 minutes[/spoiler]. Remember that the start time of B is 4:10pm.
B leaves later than A so it first needs to catch up to A, and because it is going faster than A, B will eventually overtake A.
At 4:10 pm, A has covered 2/3 of what it would cover in 1 hour (40/60 minutes), so 60 x 2/3 = 40 miles.
Let's do a table of the trains after every hour:
[Time lapsed] [A]
[0 hours] [40] [0]
[1 hour] [100] [75]
[2 hours] [160] [150]
[3 hours] [220] [225]
As you can see, B is already 5 miles ahead of A after 3 hours, so that means that B overtakes A a couple minutes before 3 hours have passed. The closest answer choice is [spoiler](D) 2 hours 40 minutes[/spoiler]. Remember that the start time of B is 4:10pm.
-
- Master | Next Rank: 500 Posts
- Posts: 447
- Joined: Fri Nov 08, 2013 7:25 am
- Thanked: 25 times
- Followed by:1 members