BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

pt question

Expert replies
by jamesk486 » Sun May 06, 2007 8:20 am
The price of a dress was first discounted by a certain percent and later by 25 percent of the discounted price. If these two discounts are equivalent to a single discount of 40% of the original price, what was the first discount?
A. 10%
B. 15%
C. 20%
D. 30%
E. 65%

The rear wheels of a car crossed a certain line 0.5 second after the front wheels crossed the same line. If the centers of the front and rear wheels are 20 feet apart and the car traveled in a straight line at a constant speed, which of the following gives the speed of the car in miles per hour?

A. (20/5.280)(60^2/0.5)
B. (20/5.280)(60/0.5)
C.(20/5.280)(0.5/60^2)
D. (20)(5.280) / (60^2)(0.5)
E. (20)(5.280) / (60)(0.5)
Join the discussion
Source: — Problem Solving |

Re: pt question

by jayhawk2001 » Sun May 06, 2007 10:21 am
jamesk486 wrote:The price of a dress was first discounted by a certain percent and later by 25 percent of the discounted price. If these two discounts are equivalent to a single discount of 40% of the original price, what was the first discount?
A. 10%
B. 15%
C. 20%
D. 30%
E. 65%
Let x be the first discount.

(1-x)(.75) = 0.6

Solving for x, we get 0.2 i.e. 20%

jamesk486 wrote: The rear wheels of a car crossed a certain line 0.5 second after the front wheels crossed the same line. If the centers of the front and rear wheels are 20 feet apart and the car traveled in a straight line at a constant speed, which of the following gives the speed of the car in miles per hour?

A. (20/5.280)(60^2/0.5)
B. (20/5.280)(60/0.5)
C.(20/5.280)(0.5/60^2)
D. (20)(5.280) / (60^2)(0.5)
E. (20)(5.280) / (60)(0.5)
I guess we need the conversion factor between feet and miles to
answer this.

0.5 * speed = 20 feet
0.5 / (60*60) * speed = 20 feet (convert sec to hour)

speed = (20 * 60 * 60 / 0.5) feet/hr
speed = (20 * 60 * 60) / (0.5 * 5280) miles/hr

I'm not too sure if GMAT expects you to remember conversion
factors from feet to miles.
Join the discussion

by Cybermusings » Sun May 06, 2007 11:44 am
The rear wheels of a car crossed a certain line 0.5 second after the front wheels crossed the same line. If the centers of the front and rear wheels are 20 feet apart and the car traveled in a straight line at a constant speed, which of the following gives the speed of the car in miles per hour?

A. (20/5.280)(60^2/0.5)
B. (20/5.280)(60/0.5)
C.(20/5.280)(0.5/60^2)
D. (20)(5.280) / (60^2)(0.5)
E. (20)(5.280) / (60)(0.5)

20 feet is the distance which is covered in .5 seconds...

20 ft = 20/5280 miles
.5 sec = .5/60*60 hrs
Speed = Distance/Time
= (20/5280) / [.5/3600]
= (20/5280)*3600/.5

So option A
Join the discussion

Re: pt question

by mmslf75 » Sun Aug 16, 2009 1:32 am
jamesk486 wrote:The price of a dress was first discounted by a certain percent and later by 25 percent of the discounted price. If these two discounts are equivalent to a single discount of 40% of the original price, what was the first discount?
A. 10%
B. 15%
C. 20%
D. 30%
E. 65%

I have yet another method to this...
When you have two such percentages acting one after the other..

a + b + (ab/100) = Effective Percentage

a - 25 + a (-25/100) = -40
a - 25 - (a/4) = -40
3a = - 160 + 100
a = -20 => Discount of 20 percent
Join the discussion