9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3 small boxes. The number of ways of
arranging one ball in each of the boxes is
(a) 18720
(b)18270
(c)17280
(d)12780
help me to solve it......
Arrangement problem........
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No. of ways 5 balls can be placed in 6 boxes (except 3 small boxes) = 6P5 = 6!/(6-5)! = 6*5*4*3*2 = 720 waysaarati wrote:9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3 small boxes. The number of ways of
arranging one ball in each of the boxes is
(a) 18720
(b)18270
(c)17280
(d)12780
help me to solve it......
Remaining balls = 4
No. of ways 4 balls can be placed in 3 small boxes = 4P3 = 4!/(4-3)! = 4*3*2 = 24 ways
Number of ways of arranging one ball in each of the boxes = 720 * 24 = 17,280
The correct answer is (C).
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Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
thank u very much.... is there any way to solve this type of problems...Rahul@gurome wrote:No. of ways 5 balls can be placed in 6 boxes (except 3 small boxes) = 6P5 = 6!/(6-5)! = 6*5*4*3*2 = 720 waysaarati wrote:9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3 small boxes. The number of ways of
arranging one ball in each of the boxes is
(a) 18720
(b)18270
(c)17280
(d)12780
help me to solve it......
Remaining balls = 4
No. of ways 4 balls can be placed in 3 small boxes = 4P3 = 4!/(4-3)! = 4*3*2 = 24 ways
Number of ways of arranging one ball in each of the boxes = 720 * 24 = 17,280
The correct answer is (C).