$$\left(\sqrt{7+4\sqrt{3}}+\sqrt{7-4\sqrt{3}}\right)^2$$ is equal to which of the following?
A. 32
B. 30
C. 24
D. 16
E. 12
(7+43+7-43)^2 is equal to which of the following?
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- Max@Math Revolution
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√3 ≈ 1.7.Max@Math Revolution wrote:$$\left(\sqrt{7+4\sqrt{3}}+\sqrt{7-4\sqrt{3}}\right)^2$$ is equal to which of the following?
A. 32
B. 30
C. 24
D. 16
E. 12
7 + 4√3 ≈ 7 + (4)(1.7) = 13.8.
7 - 4√3 ≈ 7 - (4)(1.7) = 0.2.
Thus, the given expression can be approximated as follows:
(√13.8 + √0.2)² = a little more than 13.8.
Only D is viable.
The correct answer is D.
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- fskilnik@GMATH
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$$? = {\left( {\sqrt {7 + 4\sqrt 3 } + \sqrt {7 - 4\sqrt 3 } } \right)^2} = {\left( {A + B} \right)^2}$$Max@Math Revolution wrote:$$\left(\sqrt{7+4\sqrt{3}}+\sqrt{7-4\sqrt{3}}\right)^2$$ is equal to which of the following?
A. 32
B. 30
C. 24
D. 16
E. 12
$${A^2} = 7 + 4\sqrt 3 $$
$${B^2} = 7 - 4\sqrt 3 $$
$$2AB = 2\sqrt {\left( {7 + 4\sqrt 3 } \right)\left( {7 - 4\sqrt 3 } \right)} = 2\sqrt {{7^2} - {{\left( {4\sqrt 3 } \right)}^2}} = 2\sqrt {49 - 48} = 2$$
$$? = \left( {7 + 4\sqrt 3 } \right) + \left( {7 - 4\sqrt 3 } \right) + 2 = 16$$
This solution follows the notations and rationale taught in the GMATH method.
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Fabio.
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- Max@Math Revolution
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=>
You should recall two properties about nested radicals:
$$\sqrt{a+b+2\sqrt{ab}}=\sqrt{a}+\sqrt{b}$$ ,
$$\sqrt{a+b-2\sqrt{ab}}=\sqrt{a}-\sqrt{b}$$ , where a > b.
Together, these yield
$$\left(\sqrt{7+4\sqrt{3}}+\sqrt{7-4\sqrt{3}}\right)^2$$
$$=\left(\sqrt{7+2\sqrt{12}}+\sqrt{7-2\sqrt{12}}\right)^2$$
$$=\left(\sqrt{4}+\sqrt{3}+\sqrt{4}-\sqrt{3}\right)^2$$
$$=\left(2\sqrt{4}\right)^2$$
$$=16$$
Therefore, the answer is D.
Answer: D
You should recall two properties about nested radicals:
$$\sqrt{a+b+2\sqrt{ab}}=\sqrt{a}+\sqrt{b}$$ ,
$$\sqrt{a+b-2\sqrt{ab}}=\sqrt{a}-\sqrt{b}$$ , where a > b.
Together, these yield
$$\left(\sqrt{7+4\sqrt{3}}+\sqrt{7-4\sqrt{3}}\right)^2$$
$$=\left(\sqrt{7+2\sqrt{12}}+\sqrt{7-2\sqrt{12}}\right)^2$$
$$=\left(\sqrt{4}+\sqrt{3}+\sqrt{4}-\sqrt{3}\right)^2$$
$$=\left(2\sqrt{4}\right)^2$$
$$=16$$
Therefore, the answer is D.
Answer: D
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We can look at the given expression as the quadratic identity of (x + y)^2 = x^2 + y^2 + 2xy, and thus:Max@Math Revolution wrote:$$\left(\sqrt{7+4\sqrt{3}}+\sqrt{7-4\sqrt{3}}\right)^2$$ is equal to which of the following?
A. 32
B. 30
C. 24
D. 16
E. 12
x^2 = 7 + 4√3
y^2 = 7 - 4√3
Next we can determine the value of 2xy:
2(√(7 + 4√3)(√(7 - 4√3)
2√[(7 + 4√3)(7 - 4√3)]
Using the difference of squares, we have:
2√[7^2 - (4√3)^2]
2√(49 - 48) = 2
Thus, the final value is:
(7 + 4√3) + (7 - 4√3) + 2 = 16
Answer: D
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