cant understand OG 12 - DS Q 121

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cant understand OG 12 - DS Q 121

by dotnetuncle » Sun Nov 15, 2009 9:09 am
121. In the xy-plane, region R consists of all the points (x,y) such that 2x+3y<=6. Is the point (r,s) in the region R?

1) 3r + 2s = 6
2) r<=3 and s<=2

Whats the approach & solution?

Cheers
du

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by life is a test » Sun Nov 15, 2009 6:45 pm
IMO D

from original eqn if you set x=0 then y<=2 and if you set x = 0, then y>=2 -> this tell us that region R is in the bottom corner of the x-y axis (i.e. in the +ve x and -ve y quadrant).

1. we can set s =0 and determine r value and similarly determine s by setting r=0 -> suff to determine which quadrant r and s lie in.

2. values given directly hence suff.

hope that helps

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by linfongyu » Wed Nov 18, 2009 3:17 pm
It's either C or E.

2x+3y<=6 is the equation of a line, negative slope of -2/3, shaded to the left of the line.

1. Equation of a line, slope of -3/2. Since it has a different slope than the prompt, they are not parallel and must intersect at some point. Therefore Insufficient. Eliminate A, D.

2. If we take the maximum values (3,2), 2*3+3*2=12, which is greater than 6. If the values are (0,0), 2*0+3*0=0, which is less than 6. Insufficient Eliminate B.

Combine:
This is where I run into trouble. Can someone offer a suggestion? I pretty much guessed between C and E.

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by palvarez » Wed Nov 18, 2009 3:57 pm
Look at the intersection point 3x+2y = 6, 2x+3y = 6

(6/5, 6/5). This critical point is with "x<=3 and y<=2"


So, insufficient. Best way: just draw geometrically

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by 2010gmat » Thu Nov 19, 2009 4:45 am
IMO B

wats the OA

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by 2010gmat » Thu Nov 19, 2009 4:57 am
wud like to correct myself...shud be E....as someone mentioned just draw the graphs

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by Abdulla » Fri Nov 20, 2009 6:49 pm
Guys, can someone explain this question pls?
Abdulla

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by geemat » Fri Nov 20, 2009 8:33 pm
Look at figures for explanation
Attachments
1.jpg
2.jpg

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by lunarpower » Thu Dec 03, 2009 1:54 am
dotnetuncle wrote:121. In the xy-plane, region R consists of all the points (x,y) such that 2x+3y<=6. Is the point (r,s) in the region R?

1) 3r + 2s = 6
2) r<=3 and s<=2

Whats the approach & solution?

Cheers
du
so, first, rephrase. you can simplify the question to, "is 2r + 3s < 6?"

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statement (2) is easier, so let's start with that one.

takeaway: if you're given RANGES or INEQUALITIES in a data sufficiency problem, you should TEST THE EXTREMES.

the biggest that r and s can be are, respectively, 3 and 2.
therefore, the largest possible value of (2r + 3s) is 12. this is a "no" to the question.

the smallest that r and s can be are huge negative numbers.
therefore, it's possible for (2r + 3s) to be a huge negative number. this is a "yes" to the question.

insufficient.

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statement (1):

there's a really quick VISUAL STRATEGY if you have enough visual intuition about these sorts of things.
namely:
the line 2x + 3y = 6 (the line that produces the inequality in the prompt) is not parallel to the line 3x + 2y = 6 (the line in statement 1).
therefore, the lines will intersect. therefore, each line will have points on both sides of the other one.
therefore, since the inequality is only on one side of the line 2x + 3y = 6, statement (1) will have points that are both inside and outside the region defined by that inequality.
so, insufficient.

if not, then, you can consider this equation and inequality to be simultaneous, and you can SUBSTITUTE.
get a substitution: 3r + 2s = 6 --> s = 3 - 1.5r. (note that you have to get the substitution from the equation - you can't generally get a substitution from an inequality)
therefore, any point on the line 3r + 2s = 6 can be defined by (r, 3 - 1.5r).
plug these into the prompt:
is 2r + 3s < 6?
is 2r + 3(3 - 1.5r) < 6?
is 9 - 4.5r < 6?
insufficient, since (9 - 4.5r) can have any value at all.

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together:

from (1), the question is now "is 9 - 4.5r < 6?"

from (2), r is anything < 3.
this means that (9 - 4.5r) can be anything > 9 - 4.5(3), or -4.5.
some of these values are less than 6; others are greater than 6.
insufficient.

ans (e)

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...or you could just do what they do in the back of the official guide, and find points that prove that the two statements together are insufficient.
Ron has been teaching various standardized tests for 20 years.

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