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by f2006198 » Tue Nov 17, 2009 10:00 pm
IMO E

There are four distinct sets

1.explosive-alert
2.explosive-no alert
3.no explosive-alert
4.no explosive-no alert

Clearly sets (1&2) are independent of sets (3&4). The author has given information only on (3&4) and proceeds to draw a conclusion about (1&2) which is flawed. Hence the answer.
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by heshamelaziry » Tue Nov 17, 2009 10:16 pm
There is no OA here or at thegmatclub.com, but guys who support E seem quite confident. I read all explanation for E, but don't understand what probability ahs to do with the question?

Anyone one would like to give a down to earth explanation? easy and straightforward.
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by mehravikas » Wed Nov 18, 2009 12:06 pm
We need Testluv :-)
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by heshamelaziry » Wed Nov 18, 2009 1:15 pm
I bet that A is the answer
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by mariah » Wed Nov 18, 2009 1:20 pm
that's say we have 100 baggage all without explosive!!!
and detector gave false alarm to 1 baggage...

but the argument states that 99 baggage will have explosive ...

it clearly substitutes one group for a different group!
Last edited by mariah on Wed Nov 18, 2009 1:26 pm, edited 1 time in total.
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by heshamelaziry » Wed Nov 18, 2009 1:23 pm
mariah wrote:that's say we have 100 baggage all without explosive!!!
and detector gave false alarm to 1 baggage...

stimulus says that 99 baggage will have explosive ...

it clearly substitutes one group for a different group!

Hi maria,


Which groups were substituted ? I don't think the conclusion is doing so.
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by mariah » Wed Nov 18, 2009 1:34 pm
E is the best choice for me
all the rest are irrevelant
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