clock60 wrote:my little try
what is r-?
(1) |r-0|=3|m-0|. |r|=3*|m|, we can`t extract the value of r from here. so insuff
(2) (m+r)/2=12. m+r=24. also insuff
both
m=24-r, from 2st, and insert in 1 st
|r|=3*|24-r| we need to solve this one, but again no the only value for r,
r=36. 36=3*12.
r=18, 18=3*6
i would pick E
Be careful. You arrived at the correct answer, but your reasoning is faulty: r=36 and m=12 do not satisfy statement 2 because 12 is not halfway between 12 and 36.
Statement 1: |r|=3*|m|.
Statement 2: m+r = 24
The answer following values satisfy both statements:
r=18 and m=6:
|18| = 3*|6|
18+6 = 24
r=36 and m=-12:
|36| = 3*|-12|
36+-12 = 24
Since r=18 and r=36 both work, insufficient.
The correct answer is E.
Always consider negative values when asked about distances on a number line. And be very careful if you try to solve algebraically. Plugging in actual numbers is safer.
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