Today Rebecca, who is 34 years old, and her daughter, who is 8 years old, celebrate their birthdays. How many years will pass before Rebecca's age is twice her daughter's age?
A. 10
B. 14
C. 18
D. 22
E. 26
The OA is C
Source: Official Guide
Today Rebecca, who is 34 years old, and her daughter, who is
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I think the best (i.e., fastest) approach is to TEST the answer choices.swerve wrote:Today Rebecca, who is 34 years old, and her daughter, who is 8 years old, celebrate their birthdays. How many years will pass before Rebecca's age is twice her daughter's age?
A. 10
B. 14
C. 18
D. 22
E. 26
The OA is C
Source: Official Guide
However, for those who prefer using algebra, here's an algebraic approach:
Let x be the number of years from today.
So, x years in the future, Rebecca's age will be 34 + x
And, x years in the future, her daughter's age will be 8 + x
We want Rebecca's future age to be twice her daughter's future age.
We can create the following "word equation": (Rebecca's future age) = 2(daughter's future age)
Or we can write: (34 + x) = 2(8 + x)
Expand to get: 34 + x = 16 + 2x
Solve to get: x = 18
Answer: C
Cheers,
Brent
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- Jeff@TargetTestPrep
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We are given that Rebecca is 34 and her daughter is 8. We can let n = the number of years until Rebecca is twice as old as her daughter. At that time, Rebecca will be (34 + n) years old, and her daughter will be (8 + n) years old, and Rebecca will be twice her daughter's age:swerve wrote:Today Rebecca, who is 34 years old, and her daughter, who is 8 years old, celebrate their birthdays. How many years will pass before Rebecca's age is twice her daughter's age?
A. 10
B. 14
C. 18
D. 22
E. 26
The OA is C
Source: Official Guide
34 + n = 2(8 + n)
34 + n = 16 + 2n
18 = n
Answer: C
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