BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Set M is composed of the positive even integers up to 100.

Expert replies
by swerve » Wed Mar 13, 2019 7:15 am

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty—

Set M is composed of the positive even integers up to 100. Set N is composed of the odd integers from -1 to 99. What is the value of (the sum of set M)-(the sum of set N)?

A. 49
B. 50
C. 51
D. 100
E. 101

The OA is C

Source: Magoosh
Join the discussion
Source: — Problem Solving |

swerve wrote:Set M is composed of the positive even integers up to 100. Set N is composed of the odd integers from -1 to 99. What is the value of (the sum of set M)-(the sum of set N)?

A. 49
B. 50
C. 51
D. 100
E. 101

The OA is C

Source: Magoosh
Set M is composed of the positive even integers up to 100.
Set M = {2, 4, 6, 8, . . . . 96, 98, 100}

Set N is composed of the odd integers from -1 to 99
Set N = {-1, 1, 3, 5, . . . 95, 97, 99}

What is the value of (the sum of Set M) - (the sum of Set N)?
SUM of set M = 2 + 4 + 6 + 8 + . . . .+ 96 + 98 + 100
SUM of set N = -1 + 1 + 3 + 5 + . . . 95 + 97 + 99

ASIDE: Notice that there are 100 POSITIVE integers from 1 to 100 inclusive
HALF of them are EVEN and HALF are ODD

So, set M consists of 50 integers
and set N consists of 51 integers (since set N also has one NEGATIVE odd number)

(the sum of Set M) - (the sum of Set N) = (2 + 4 + 6 + 8 + . . . .+ 96 + 98 + 100) - (-1 + 1 + 3 + 5 + . . . 95 + 97 + 99)
= (2 + 4 + 6 + 8 + . . . .+ 96 + 98 + 100) - (1 + 3 + 5 + . . . 95 + 97 + 99) + 1
= (2 - 1) + (4 - 3) + (6 - 5) + . . . + (98 - 97) + (100 - 99) + 1
= (1) + (1) + (1) + . . . + (1) + (1) + 1
= 50 + 1 [since we have 50 PAIRS of even and odd numbers]
= 51

Answer: C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by GMATGuruNY » Wed Mar 13, 2019 9:20 am
swerve wrote:Set M is composed of the positive even integers up to 100. Set N is composed of the odd integers from -1 to 99. What is the value of (the sum of set M)-(the sum of set N)?

A. 49
B. 50
C. 51
D. 100
E. 101
For any EVENLY SPACED SET:
Count = (biggest - smallest)/(increment) + 1.
Average = (biggest + smallest)/2.
Sum = (count)(average).
The INCREMENT is the difference between successive values.

Even integers between 2 and 100, inclusive:
Here, the integers are EVEN, so the increment = 2.
Count = (100-2)/2 + 1 = 50.
Average = (100+2)/2= 51.
Sum = (50)(51).

Odd integers between -1 and 99, inclusive:
Here, the integers are ODD, so the increment = 2.
Count = (99-(-1))/2 + 1 = 51.
Average = (99+(-1))/2= 49.
Sum = (51)(49).

Subtracting the second sum from the first, we get:
(50*51) - (51*49) = 51(50-49) = 51*1 = 51.

The correct answer is C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by Scott@TargetTestPrep » Fri Mar 15, 2019 6:50 am
swerve wrote:Set M is composed of the positive even integers up to 100. Set N is composed of the odd integers from -1 to 99. What is the value of (the sum of set M)-(the sum of set N)?

A. 49
B. 50
C. 51
D. 100
E. 101

The OA is C

Source: Magoosh
The number of integers in set M is (100 - 2)/2 + 1 = 50

The number of integers in Set N is (99 - (-1))/2 + 1 = 51

We can pair the 50 numbers from set M with the first 50 numbers from set N as follows:

2, -1

4, 1

6, 3, etc.

We see that each number in set M is 3 more than each number in set N. Thus, comparing the first 50 numbers in each set, the sum of those numbers in Set M is 3 x 50 = 150 greater.

However, set N has an extra number, which is 99.

So the overall sum of the integers in set M is actually 150 - 99 = 51 greater than the sum of the integers in set N.

Answer: C

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Join the discussion