Inequalities

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Inequalities

by dkumar.83 » Sun May 09, 2010 10:50 am
Image

Hi, The answer is A. Kindly provide the explanation for the same.

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by iamseer » Sun May 09, 2010 11:09 am
vmt not equal 0. Therefore none of them is zero.
from 1:
m>v^2
therefore m >0
therefore v^2*m^3*t^4>0 (only m could make this negative, squares and forth powers are always positive)
Sufficient

from 2:
m>t^4
again m>0
therefore v^2*m^3*t^4>0
Sufficient

IMO answer D
"Choose to chance the rapids and dance the tides"

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by ballubalraj » Mon May 10, 2010 11:53 pm
I agree with above explanation.

Could you please recheck the OA?

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by gmatmachoman » Tue May 11, 2010 12:15 am
iamseer wrote:vmt not equal 0. Therefore none of them is zero.
from 1:
m>v^2
therefore m >0
therefore v^2*m^3*t^4>0 (only m could make this negative, squares and forth powers are always positive)
Sufficient

from 2:
m>t^4
again m>0
therefore v^2*m^3*t^4>0
Sufficient

IMO answer D
seer bhai!
In my screen shot its showing
m> t ^(-4)
> 1/(t^4)
m>0

even if t is a imaginary number, m>0

SO pick D

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by iamseer » Tue May 11, 2010 8:25 am
gmatmachoman wrote: seer bhai!
In my screen shot its showing
m> t ^(-4)
> 1/(t^4)
m>0

even if t is a imaginary number, m>0

SO pick D
yes, you are right. Thanks for pointing that gmatmachoman.

the explanation holds as long as t has an even power.
"Choose to chance the rapids and dance the tides"