![Image](https://s2.postimage.org/e8fjr.jpg)
Hi, The answer is A. Kindly provide the explanation for the same.
seer bhai!iamseer wrote:vmt not equal 0. Therefore none of them is zero.
from 1:
m>v^2
therefore m >0
therefore v^2*m^3*t^4>0 (only m could make this negative, squares and forth powers are always positive)
Sufficient
from 2:
m>t^4
again m>0
therefore v^2*m^3*t^4>0
Sufficient
IMO answer D
yes, you are right. Thanks for pointing that gmatmachoman.gmatmachoman wrote: seer bhai!
In my screen shot its showing
m> t ^(-4)
> 1/(t^4)
m>0
even if t is a imaginary number, m>0
SO pick D