What is the value of X if 3^(2x-2)-5*3^(x-2)-66 =0?
A. 2
B. 3
C. 4
D. 5
E. 6
A good PS.
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- gmat_perfect
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3^(x-2)(3^x - 5)=66gmat_perfect wrote:What is the value of X if 3^(2x-2)-5*3^(x-2)-66 =0?
A. 2
B. 3
C. 4
D. 5
E. 6
plug in A) 3^0 *( 3^2 -5)=4; B) 3^1* (3^3 -5)=66
IOM B
- saurabh_maths
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IMO it is B.
Simplify the equation. Assume 3^x = a in the equation and write it down again.
It will come into this form (a^2)/9 - (5a)//9 = 66
solve this . a = 27 or -22.
now put 3^x = 27 ... which means x = 3
Simplify the equation. Assume 3^x = a in the equation and write it down again.
It will come into this form (a^2)/9 - (5a)//9 = 66
solve this . a = 27 or -22.
now put 3^x = 27 ... which means x = 3
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Another approach:gmat_perfect wrote:What is the value of X if 3^(2x-2)-5*3^(x-2)-66 =0?
A. 2
B. 3
C. 4
D. 5
E. 6
Now 3^(2x-2) = 9^(x-1) = 5 * 3^(x-2) + 66.
Note that 5 * 3^(x-2) always ends in 5 because 3^(x-2) is odd.
Or 5 * 3^(x-2) + 66 ends in last digit of 5 + 6 which is 1.
Or 9^(x-1) ends in 1.
So (x-1) is even.
Or x is odd.
Next, check between x =3 and x = 5.
We will get that x = 3 satisfies the equation.
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