A fudgemaker has 40 pounds of chocolate, 65% of which is dark chocolate. If she buys 10 more pounds of chocolate, 25% of which is dark chocolate, what percent of her chocolate will then be dark chocolate?
A. 48%
B. 51%
C. 54%
D. 57%
E. 60%
OA D
Source: Veritas Prep
A fudgemaker has 40 pounds of chocolate, 65% of which is dark chocolate. If she buys 10 more pounds of chocolate, 25%
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Initial weight of the chocolate = 40 pounds
% of dark chocolate in the initial mixture = 65%
Dark chocolate in the initial mixture (pounds) = 65%*40=26 pounds
Additional chocolate purchased (Pounds) = 10 pounds
% of dark chocolate in the additional purchase = 25%
Dark chocolate in the additional chocolate (Pounds) = 25%*10=2.5 pounds
Total chocolate mixture weight (pounds) = 40 + 10 = 50 pounds
Total dark chocolate in the mixture = 26 + 2.5 = 28.5 pounds
% of dark chocolate in the entire mixture = \(\frac{28.5}{50}\) = 57%
% of dark chocolate in the initial mixture = 65%
Dark chocolate in the initial mixture (pounds) = 65%*40=26 pounds
Additional chocolate purchased (Pounds) = 10 pounds
% of dark chocolate in the additional purchase = 25%
Dark chocolate in the additional chocolate (Pounds) = 25%*10=2.5 pounds
Total chocolate mixture weight (pounds) = 40 + 10 = 50 pounds
Total dark chocolate in the mixture = 26 + 2.5 = 28.5 pounds
% of dark chocolate in the entire mixture = \(\frac{28.5}{50}\) = 57%
\(65% of 40 = 26\)BTGmoderatorDC wrote: ↑Fri Aug 21, 2020 6:11 pmA fudgemaker has 40 pounds of chocolate, 65% of which is dark chocolate. If she buys 10 more pounds of chocolate, 25% of which is dark chocolate, what percent of her chocolate will then be dark chocolate?
A. 48%
B. 51%
C. 54%
D. 57%
E. 60%
OA D
Source: Veritas Prep
\(25% of 10 = 2.5\)
Total dark chocolate \(= 28.5\)
Total chocolate \(= 10+40 = 50\)
Total \(\%\) of dark chocolate \(= \dfrac{28.5}{50}\cdot 2 = 57\%\)