In how many ways can the letters of the word ABACUS be rearranged such that the vowels always appear together?
A. 6!/2!
B. 3!*3!
C. 4!/2!
D. 4!*3!/2!
E. 3!*3!/2!
The OA is D.
In how many ways can the letters of the word ABACUS...
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Since the vowels must appear together, put them together in a BLOCK: [AAU].BTGmoderatorLU wrote:In how many ways can the letters of the word ABACUS be rearranged such that the vowels always appear together?
A. 6!/2!
B. 3!*3!
C. 4!/2!
D. 4!*3!/2!
E. 3!*3!/2!
Now count the number of ways to arrange the 4 elements [AAU], B, C and S.
The number of ways to arrange 4 distinct elements = 4!.
Now we must account for the number of ways that the vowels themselves can be arranged WITHIN the [AAU] block.
The vowels can be arranged as follows:
AAU, AUA, UAA.
Total ways = 3.
Multiplying the results above, we get:
4! * 3.
This is the value yielded by answer choice D:
(4! * 3!)/2! = 4! * 3.
The correct answer is D.
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We can arrange the letters as follows:BTGmoderatorLU wrote:In how many ways can the letters of the word ABACUS be rearranged such that the vowels always appear together?
A. 6!/2!
B. 3!*3!
C. 4!/2!
D. 4!*3!/2!
E. 3!*3!/2!
[A-A-U] - B - C - S
Thinking of [A-A-U] as a single element, [A-A-U] - B - C - S can be arranged in 4! ways.
We must also consider that [A-A-U] can be arranged in 3!/2! ways (by the formula for permutations with indistinguishable objects).
Thus, the total number of ways is 4! * 3!/2!.
Answer: D
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