In the x-y plane there is a line K, (x/a)+(y/b)=1. What is t

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In the x-y plane there is a line K, (x/a)+(y/b)=1. What is the x-intercept of line K?
1) a=2b
2) a=6

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by Max@Math Revolution » Sun Jun 19, 2016 4:46 pm
We can modify the original condition and the question. When the question asks about the x-intercept, we need to find the value of x when y=0. Then, if we substitute y=0, from x/a=1, we get x=a. Hence, we all need to know the value of a. Since the condition 2) states a=6, the condition is sufficient. Thus, the correct answer is B.



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by Brent@GMATPrepNow » Fri Jun 24, 2016 10:45 am
Max@Math Revolution wrote:In the x-y plane there is a line K, (x/a)+(y/b)=1. What is the x-intercept of line K?

1) a = 2b
2) a = 6
Target question: What is the x-intercept of line K?

This is a great candidate for rephrasing the target question.
Aside: We have a video with tips on rephrasing the target question: https://www.gmatprepnow.com/module/gmat- ... cy?id=1100

Given: the equation of line K is (x/a) + (y/b) = 1.
NOTE: The x-intercept is the x-coordinate of the point where the line intersects the x-axis
IMPORTANT: At this intersection point, the y-coordinate = 0
So, let's plug y = 0 into the equation of line K
We get: (x/a) + (0/b) = 1
Simplify: (x/a) = 1
This means that x = a
In other words, the x-intercept of like K is a
So, we need only find the value of a to answer the target question.

Let's REPHRASE the target question as.....
REPHRASED target question: What is the value of a?

Statement 1: a = 2b
This is not enough info to answer the REPHRASED target question. There are several values of a and b that satisfy statement 1. Here are two:
Case a: a = 4 and b = 2, in which case a = 4
Case b: a = 6 and b = 3, in which case a = 6
Since we cannot answer the REPHRASED target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: a = 6
PERFECT!!
This allows us to answer the REPHRASED target question with certainty. So statement 2 is SUFFICIENT

Answer = B

ASIDE: For more info on finding x and y intercepts, watch this video: https://www.gmatprepnow.com/module/gmat ... /video/996

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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