How many five-digit numbers can be formed from the digits 0, 1, 2, 3, 4, and 5, if no digits can repeat and the number must be divisible by 4?
A. 36
B. 48
C. 72
D. 96
E. 144
Answer: E
Source: Veritas Prep
How many five-digit numbers can be formed from the digits 0, 1, 2, 3, 4, and 5, if no digits can repeat and the number m
This topic has expert replies
-
- Legendary Member
- Posts: 1223
- Joined: Sat Feb 15, 2020 2:23 pm
- Followed by:1 members
Timer
00:00
Your Answer
A
B
C
D
E
Global Stats
GMAT/MBA Expert
- Scott@TargetTestPrep
- GMAT Instructor
- Posts: 7294
- Joined: Sat Apr 25, 2015 10:56 am
- Location: Los Angeles, CA
- Thanked: 43 times
- Followed by:29 members
Solution:BTGModeratorVI wrote: ↑Wed Jul 29, 2020 2:51 pmHow many five-digit numbers can be formed from the digits 0, 1, 2, 3, 4, and 5, if no digits can repeat and the number must be divisible by 4?
A. 36
B. 48
C. 72
D. 96
E. 144
Answer: E
Recall that if a number is divisible by 4, the last two digits of the number must be divisible by 4. Therefore, the last two digits of the 5-digit number must be 04, 12, 20, 24, 32, 40 or 52. Furthermore, since the first digit can’t be 0, we can divide the last two digits into two groups: 1) 04, 20, 40 (where the digit 0 is used) and 2) 12, 24, 32, 52 (where the digit 0 is not used).
Group 1: The digit 0 is used as one of the last two digits
Since two digits (including 0) are used, there are 4 options for the first digit, 3 options for the second digit and 2 options for the third digit. Since the last two digits together have 3 options, the total number of five-digit numbers can be formed is 4 x 3 x 2 x 3 = 72.
Group 2: The digit 0 is not used as one of the last two digits
Since two digits (excluding 0) are used, there are 3 options for the first digit (since it can’t be 0), 3 options for the second digit and 2 options for the third digit. Since the last two digits together have 4 options, the total number of five-digit numbers can be formed is 3 x 3 x 2 x 4 = 72.
Therefore, there are a total of 72 + 72 = 144 five-digit numbers can be formed.
Answer: E
Scott Woodbury-Stewart
Founder and CEO
[email protected]
![Image](https://www.beatthegmat.com/mba/uploads/images/partners/target_test_prep/TTPsig2022.png)
See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews
![Image](https://manticoreaudio.com/wp-content/uploads/2017/07/37px-email.png)
![Image](https://manticoreaudio.com/wp-content/uploads/2017/07/37px-linked.png)
You can try as follows,BTGModeratorVI wrote: ↑Wed Jul 29, 2020 2:51 pmHow many five-digit numbers can be formed from the digits 0, 1, 2, 3, 4, and 5, if no digits can repeat and the number must be divisible by 4?
A. 36
B. 48
C. 72
D. 96
E. 144
Answer: E
Source: Veritas Prep
Total of \(600\) possible number: \(5\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1\) (zero can't be the \(1\)st digit)
Of those \(600\) number, \(300\) are even, because you have \(3\) odd and \(3\) even numbers. Of those \(300\) even numbers, about half are multiple of \(4\).
So, the correct answer is E