What is the total number of permutations of n different things taken not more than p times, when each thing may be repeated any number of times?
A. n^p +1
B. n(n^p-1)
C.n^p (n+1)/(n-1)
D. n(n^p - 1)/ (n-1)
E. n^p (n+1)
taken not more than p times
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is the answer B?
n different things- can be repeated in n different ways but only p-1 times
therefore n(n^p-1)
n different things- can be repeated in n different ways but only p-1 times
therefore n(n^p-1)
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- sureshbala
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The answer will be n+n^2+n^3+....+n^p = n(n^p-1)/n-1
Anyway, let me try to explain the concept here.
I guess every aspirant is aware of the following basic concepts.
Total number of permutations of r things from n distinct things when repetition is not allowed is nPr
Total number of permutations of r things from n distinct things when repetition is allowed is n^r
Now the given question is : we have arrange at least 1 thing and at most p things from n things and it is clearly mentioned that repetition is allowed is allowed.
1 thing can be arranged from n things in n^1 ways
2 things can be arranged from n things in n^2 ways.
............................................
.........................................
p things can be arranged from n things in n^p ways.
So the answer is n+n^2+n^3+......+n^p
This is a G.P with common ratio n (n>1)
So the sum to p terms of this G.P is n(n^p-1)/n-1
Hence D
Yes, this is definitely true.gabriel wrote:The best way to solve such questions is to substitute values for n and p.
Anyway, let me try to explain the concept here.
I guess every aspirant is aware of the following basic concepts.
Total number of permutations of r things from n distinct things when repetition is not allowed is nPr
Total number of permutations of r things from n distinct things when repetition is allowed is n^r
Now the given question is : we have arrange at least 1 thing and at most p things from n things and it is clearly mentioned that repetition is allowed is allowed.
1 thing can be arranged from n things in n^1 ways
2 things can be arranged from n things in n^2 ways.
............................................
.........................................
p things can be arranged from n things in n^p ways.
So the answer is n+n^2+n^3+......+n^p
This is a G.P with common ratio n (n>1)
So the sum to p terms of this G.P is n(n^p-1)/n-1
Hence D
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n items taken 1 time = n
n items taken 2 times where items can repeat is possible = n.n = n^2
so total permutation = n + n^2 + n^3 + ....
n(n^p-1)/(n-1)
n items taken 2 times where items can repeat is possible = n.n = n^2
so total permutation = n + n^2 + n^3 + ....
n(n^p-1)/(n-1)
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GMATPowerPrep Test2= 760
Kaplan Diagnostic Test= 700
Kaplan Test1=600
Kalplan Test2=670
Kalplan Test3=570