An investor purchased a bond for p dollars on Monday. For a certain number of days, the value of the bond increased by r percent per day. After this period of constant increase, the bond decreased the next day by q dollars and the investor decided to sell the bond that day for v dollars. When did the investor sell the bond if r = 100 {√ [(v + q)/p]} - 1?
(A) Wednesday of the same week
(B) Thursday of the same week
(C) Friday of the same week
(D) Monday of the next week'
(E) Tuesday of the next week
r = 100 {√ [(v + q)/p]} – 1
This topic has expert replies
- sanju09
- GMAT Instructor
- Posts: 3650
- Joined: Wed Jan 21, 2009 4:27 am
- Location: India
- Thanked: 267 times
- Followed by:80 members
- GMAT Score:760
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
-
- Legendary Member
- Posts: 1337
- Joined: Sat Dec 27, 2008 6:29 pm
- Thanked: 127 times
- Followed by:10 members
Monday's price --> p
n days' flotation --> p*(1+r/100)^n
last day's decrease --> -q
______ ? weekday___ Final prices --> p*(1+r/100)^n - q = v; r= 100 {√ [(v + q)]/p} - 1; find n-?
(p+(v+q)-p)^n - q = v, (v+q)^n/2 = v+q, n/2=1, n=2
@sanju, I figured answer Opps two days passed since Monday + the last day of sales (when price went down - q) makes three days, therefore answer B
BUT the problem's stem had to be modified by me as r= 100 {√ [(v + q)]/p}, otherwise I get √p*{(v+q)^(n/2-1)}=1
n days' flotation --> p*(1+r/100)^n
last day's decrease --> -q
______ ? weekday___ Final prices --> p*(1+r/100)^n - q = v; r= 100 {√ [(v + q)]/p} - 1; find n-?
(p+(v+q)-p)^n - q = v, (v+q)^n/2 = v+q, n/2=1, n=2
@sanju, I figured answer Opps two days passed since Monday + the last day of sales (when price went down - q) makes three days, therefore answer B
BUT the problem's stem had to be modified by me as r= 100 {√ [(v + q)]/p}, otherwise I get √p*{(v+q)^(n/2-1)}=1
sanju09 wrote:An investor purchased a bond for p dollars on Monday. For a certain number of days, the value of the bond increased by r percent per day. After this period of constant increase, the bond decreased the next day by q dollars and the investor decided to sell the bond that day for v dollars. When did the investor sell the bond if r = 100 {√ [(v + q)/p]} - 1?
(A) Wednesday of the same week
(B) Thursday of the same week
(C) Friday of the same week
(D) Monday of the next week'
(E) Tuesday of the next week
My knowledge frontiers came to evolve the GMATPill's methods - the credited study means to boost the Verbal competence. I really like their videos, especially for RC, CR and SC. You do check their study methods at https://www.gmatpill.com
- manpsingh87
- Master | Next Rank: 500 Posts
- Posts: 436
- Joined: Tue Feb 08, 2011 3:07 am
- Thanked: 72 times
- Followed by:6 members
IMO Bsanju09 wrote:An investor purchased a bond for p dollars on Monday. For a certain number of days, the value of the bond increased by r percent per day. After this period of constant increase, the bond decreased the next day by q dollars and the investor decided to sell the bond that day for v dollars. When did the investor sell the bond if r = 100 {√ [(v + q)/p]} - 1?
(A) Wednesday of the same week
(B) Thursday of the same week
(C) Friday of the same week
(D) Monday of the next week'
(E) Tuesday of the next week
v+q = (1+r/100)^n*p;
Subsituting this in a equation we get;
r= 100(1+r/100)^n/2 - 1;
for n=2; we will not get any solution;
for n=4; we will have r=1;
Therefore answer should be B
Anyways good question...sanju..!!
O Excellence... my search for you is on... you can be far.. but not beyond my reach!