r = 100 {√ [(v + q)/p]} – 1

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r = 100 {√ [(v + q)/p]} – 1

by sanju09 » Wed Mar 02, 2011 5:14 am
An investor purchased a bond for p dollars on Monday. For a certain number of days, the value of the bond increased by r percent per day. After this period of constant increase, the bond decreased the next day by q dollars and the investor decided to sell the bond that day for v dollars. When did the investor sell the bond if r = 100 {√ [(v + q)/p]} - 1?
(A) Wednesday of the same week
(B) Thursday of the same week
(C) Friday of the same week
(D) Monday of the next week'
(E) Tuesday of the next week
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by Night reader » Wed Mar 02, 2011 6:41 am
Monday's price --> p

n days' flotation --> p*(1+r/100)^n
last day's decrease :( --> -q
______ ? weekday___ Final prices --> p*(1+r/100)^n - q = v; r= 100 {√ [(v + q)]/p} - 1; find n-?

(p+(v+q)-p)^n - q = v, (v+q)^n/2 = v+q, n/2=1, n=2

@sanju, I figured answer Opps two days passed since Monday + the last day of sales (when price went down - q) makes three days, therefore answer B

BUT the problem's stem had to be modified by me as r= 100 {√ [(v + q)]/p}, otherwise I get √p*{(v+q)^(n/2-1)}=1
sanju09 wrote:An investor purchased a bond for p dollars on Monday. For a certain number of days, the value of the bond increased by r percent per day. After this period of constant increase, the bond decreased the next day by q dollars and the investor decided to sell the bond that day for v dollars. When did the investor sell the bond if r = 100 {√ [(v + q)/p]} - 1?
(A) Wednesday of the same week
(B) Thursday of the same week
(C) Friday of the same week
(D) Monday of the next week'
(E) Tuesday of the next week
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by manpsingh87 » Wed Mar 02, 2011 9:38 am
sanju09 wrote:An investor purchased a bond for p dollars on Monday. For a certain number of days, the value of the bond increased by r percent per day. After this period of constant increase, the bond decreased the next day by q dollars and the investor decided to sell the bond that day for v dollars. When did the investor sell the bond if r = 100 {√ [(v + q)/p]} - 1?
(A) Wednesday of the same week
(B) Thursday of the same week
(C) Friday of the same week
(D) Monday of the next week'
(E) Tuesday of the next week
IMO B

v+q = (1+r/100)^n*p;

Subsituting this in a equation we get;

r= 100(1+r/100)^n/2 - 1;

for n=2; we will not get any solution;
for n=4; we will have r=1;
Therefore answer should be B

Anyways good question...sanju..!!
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