Harvey teaches a certain number of biology students in 2 classes, K and L. He can divide the students in class K into 7 groups of n students each. He can divide the students in class L into 6 groups of p students each with 1 student left over. How many students are in class L ?
(1) n = p
(2) There are 5 more students in class K than in class L.
I think it is B
oa IS c
Harvey
This topic has expert replies
Hi,
I thought the answer was B as well, but after looking at OA, I spent some more time on it.
With (2) there are more than 1 answers possible,
42 = 7*6 , 37 = 6*6+1 (which is the correct answer) and we can get this with (1) also.
but. consider
84 = 7*12, 79 = 6*13+1 -- this satisfies too. And unless we have (1)s aying n=p, we cannot center in on 42,37. which is the answer to the questions.
So OA = C is correct.
I thought the answer was B as well, but after looking at OA, I spent some more time on it.
With (2) there are more than 1 answers possible,
42 = 7*6 , 37 = 6*6+1 (which is the correct answer) and we can get this with (1) also.
but. consider
84 = 7*12, 79 = 6*13+1 -- this satisfies too. And unless we have (1)s aying n=p, we cannot center in on 42,37. which is the answer to the questions.
So OA = C is correct.
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Harvey teaches a certain number of biology students in 2 classes, K and L. He can divide the students in class K into 7 groups of n students each. He can divide the students in class L into 6 groups of p students each with 1 student left over. How many students are in class L ?
(1) n = p
(2) There are 5 more students in class K than in class L.
Hi,
I solved it like this:
Given:
K = 7n and M = 6p + 1
From (1)
K = 7p and M = 6P + 1 ... NS
From (2)
K = L+5 ... NS
From 1 and 2
7p = (6p + 1) + 5... Sufficienet, Therefore C
(1) n = p
(2) There are 5 more students in class K than in class L.
Hi,
I solved it like this:
Given:
K = 7n and M = 6p + 1
From (1)
K = 7p and M = 6P + 1 ... NS
From (2)
K = L+5 ... NS
From 1 and 2
7p = (6p + 1) + 5... Sufficienet, Therefore C
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Harvey teaches a certain number of biology students in 2 classes, K and L. He can divide the students in class K into 7 groups of n students each. He can divide the students in class L into 6 groups of p students each with 1 student left over. How many students are in class L ?
(1) n = p
(2) There are 5 more students in class K than in class L.
Should be C.
Solving gives n=p=6
(1) n = p
(2) There are 5 more students in class K than in class L.
Should be C.
Solving gives n=p=6