If xy ≠0, is x > y?
(1) 4x = 3y
(2) |y - x| = x - y
xy
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1) is not sufficient (when x is -ve x>y and when x is positive x<y)gmatnmein2010 wrote:If xy ≠0, is x > y?
(1) 4x = 3y
(2) |y - x| = x - y
2) |y - x| = x - y => x-y is positive x>y
Sufficient
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s1) not suffgmatnmein2010 wrote:If xy ≠0, is x > y?
(1) 4x = 3y
(2) |y - x| = x - y
for +ve x and +ve eqn of s1)------->x<y &
for -ve value of x and y------>x>y
s2)This means that equation |y-x|=x-y holds true when x-y>=0
bcoz ly-xl is a +ve entity
so x>=y not suff
(1)+(2) From (1) we got that x#y and from (2) x>=y , hence x>y. Sufficient.
IMO C
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1.)4x = 3y
If x = 3 and y = 4
then we get an answer NO for is x>y
If x=-3 and y = -4
then we get an answer YES for is x >y
hence statement 1 is sufficient.
2.)|y - x| = x - y
only when x is greater than y is this possible.
Hence B
If x = 3 and y = 4
then we get an answer NO for is x>y
If x=-3 and y = -4
then we get an answer YES for is x >y
hence statement 1 is sufficient.
2.)|y - x| = x - y
only when x is greater than y is this possible.
Hence B
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Hey bhumika,bhumika.k.shah wrote:1.)4x = 3y
If x = 3 and y = 4
then we get an answer NO for is x>y
If x=-3 and y = -4
then we get an answer YES for is x >y
hence statement 1 is sufficient.
2.)|y - x| = x - y
only when x is greater than y is this possible.
Hence B
I think you missed the case when (x-y) = 0
In that case also,|y - x| will be equal to x - y as |0| = 0.
Hence,x can be => y but we cannot surely say if it is not equal.
Hence,St. B would be insufficient.
I would go with C over here.
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whats the OA ?
if thts the case , then whats the purpose of giving xy is not equal to 0 in the question ?
if thts the case , then whats the purpose of giving xy is not equal to 0 in the question ?
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gmatnmein2010 wrote:If xy ≠0, is x > y?
(1) 4x = 3y
(2) |y - x| = x - y
St.1 : 4x=3y --> x= 3/4 y for +ve y x<y but for -ve y x>y not sufficient
St.2: |y - x| = x - y --> y-x <=0 --> x>=y not sufficient
combined : x=y case is removed====sufficient
Ans C
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