In a triangle ACB, if
a) angle ACB is a right angle
b) CE intersects AB
c) and CB = 5
what is the length of side AB?
(1) CE is perpendicular to AB
(2) AE = EB
OA is C But I am getting A
Could anyone please explain?
Thanks!
What's AB?
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It's Answer is C!Juggernaut_86 wrote:In a triangle ACB, if
a) angle ACB is a right angle
b) CE intersects AB
c) and CB = 5
what is the length of side AB?
(1) CE is perpendicular to AB
(2) AE = EB
OA is C But I am getting A
Could anyone please explain?
Thanks!
Only by using two statements, you'll be able to calculate the Side AB for the triangle.
- sl750
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Statement 1 tells us that CE bisects the Hypotenuse, therefore BE=AE, we have two congruent triangles
As BC=5, we can use the 45:45:90 rule and find out the length of AB, which is, 5*sqrt(2). Sufficient
Statement 2 tells us the same thing. If BE=AE, that means CE is perpendicular to AB. Sufficient
As BC=5, we can use the 45:45:90 rule and find out the length of AB, which is, 5*sqrt(2). Sufficient
Statement 2 tells us the same thing. If BE=AE, that means CE is perpendicular to AB. Sufficient
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This is incorrect.
First, note that there is nothing that tells us that E is on the line segment AB. We just know that CE intersects AB. This doesn't actually affect the answer though.
Only when we combine the statements can we conclude that ACB is a 45-45-90 triangle, which allows us to find AB.
First, note that there is nothing that tells us that E is on the line segment AB. We just know that CE intersects AB. This doesn't actually affect the answer though.
Even if E is on AB, this does NOT mean that AE = BE. This just means what it says, which is that CE and AB intersect at a right angle. If you draw a 5-12-13 right triangle, and draw a line CE that is perpendicular to the hypotenuse, you will see that this does not split AB into equal parts. Statement 1 is insufficient.(1) CE is perpendicular to AB
Without known anything about CE, this fact alone tells us nothing about AB. It just tells us that E happens to be its midpoint.(2) AE = EB
Only when we combine the statements can we conclude that ACB is a 45-45-90 triangle, which allows us to find AB.
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Only when we combine the statements can we conclude that ACB is a 45-45-90 triangle, which allows us to find AB.gmatboost wrote:This is incorrect.
First, note that there is nothing that tells us that E is on the line segment AB. We just know that CE intersects AB. This doesn't actually affect the answer though.
Even if E is on AB, this does NOT mean that AE = BE. This just means what it says, which is that CE and AB intersect at a right angle. If you draw a 5-12-13 right triangle, and draw a line CE that is perpendicular to the hypotenuse, you will see that this does not split AB into equal parts. Statement 1 is insufficient.(1) CE is perpendicular to AB
Without known anything about CE, this fact alone tells us nothing about AB. It just tells us that E happens to be its midpoint.(2) AE = EB
Only when we combine the statements can we conclude that ACB is a 45-45-90 triangle, which allows us to find AB.
HOW CAN WE SAY that ACB IS 45-90-45 triangle ?? bcos we don know if EC=EB
please help
If my post helped you- let me know by pushing the thanks button. Thanks
- gmatboost
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Assuming E is the midpoint of AB, consider triangles AEC and BEC:
AE = EB
Both triangles share side CE
Angles AEC and BEC are both right angles
That means that the hypotenuses of the triangles are equal: AC = CB
That is enough for us to know that ACB is 45-45-90
We could go a step further to answer your specific question:
Since ACB = 90
and angle ACE = angle BCE it must be the case that angle ACE = angle BCE = 45
This makes triangle ACE and BCE both 45-45-90 triangles.
AE = EB
Both triangles share side CE
Angles AEC and BEC are both right angles
That means that the hypotenuses of the triangles are equal: AC = CB
That is enough for us to know that ACB is 45-45-90
We could go a step further to answer your specific question:
Since ACB = 90
and angle ACE = angle BCE it must be the case that angle ACE = angle BCE = 45
This makes triangle ACE and BCE both 45-45-90 triangles.
Greg Michnikov, Founder of GMAT Boost
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It's a total of 20+ hours of expert instruction for an introductory price of just $10.
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Hi- you can see the attached doc to clear your doubt.1947 wrote:
HOW CAN WE SAY that ACB IS 45-90-45 triangle ?? bcos we don know if EC=EB
please help
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Hi sakett,
You are correct in proving that but bcos of limited time available we need to understand that
since CE is common side and AEC=CEB=90 there can be no other way but AC=CB
Thanks again !!
You are correct in proving that but bcos of limited time available we need to understand that
since CE is common side and AEC=CEB=90 there can be no other way but AC=CB
Thanks again !!
If my post helped you- let me know by pushing the thanks button. Thanks
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Well I was pressing the quote button and pressed Thank1947 wrote:Hi sakett,
You are correct in proving that but bcos of limited time available we need to understand that
since CE is common side and AEC=CEB=90 there can be no other way but AC=CB
Thanks again !!
Anyways, Dude I know this from my school days-- .. I was trying to clear your doubt because you asked the question in your previous post..