weird percentage problem

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weird percentage problem

by charmaine » Mon Jun 09, 2008 3:02 pm
one day a car rental agency rented 2/3 of its cars, including 3/5 of its cars with CD players. if 3/4 of its cars have CD players, what percentage of the cars that were not rented had CD players ?

a. 10%
b. 35%
c. 45 %
d. 66.7%
e. 90%

i gt 45% but the answer given is E
i dun understand

thanks for helping :)

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by egybs » Mon Jun 09, 2008 3:36 pm
Let's assume they have 60 cars.

This means that 20 of the cars were NOT rented.

Meanwhile, we also know that 4/5 of their cars have CD players... So 45 (4/5*60) cars have CD players.

Given that 3/5 of it's CD player equipped cars were rented, we know that they currently have 2/5 left. 2/5*45 = 18.

The question asks us to find the percentage of all remaining (not rented) cars that have CD players... so 18/20 = 90/100 = 90%

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by VerbalAttack » Tue Jun 10, 2008 12:46 am
hi egybs,

your explanation is correct but there are some typos..

Here is rewritten explanation;

Assume total cars = 60

Rented = (2/3) * 60 = 40; Not Rented = 20

Cars with CDs = (3/4) * 60 = 45,
Cars Rented with CDs = (3/5) * 45 = 27

Cars Not Rented with CDs = 45 - 27 = 18

% of Cars with CDs Not Rented to Cars Not Rented = (18/20) * 100 = 90%

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by egybs » Tue Jun 10, 2008 6:56 am
oops... i gotta reread what i write... thx :oops:

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by Malolo355 » Fri Sep 27, 2013 10:54 am
I don't get it...
I go over and over again that problem and I keep having the same result..35% (B)
Is there any other solution other than assuming that we have 60 cars?
Can someone pls enlighten me?

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by Brent@GMATPrepNow » Fri Sep 27, 2013 11:13 am
Malolo355 wrote:I don't get it...
I go over and over again that problem and I keep having the same result..35% (B)
Is there any other solution other than assuming that we have 60 cars?
Can someone pls enlighten me?
Since the question is asking us to find a certain percent, it's MUCH easier to begin with a number of cars that we can quickly find 2/3 of, 3/5 of and 3/4 of.
So, we need a number that is divisible by 3, 5 and 4 (the denominators of the fractions). One such number is 60, but 120, 180, etc would also work.

To mix things up, let's go from the position that there are 120 cars altogether.
One day a car rental agency rented 2/3 of its cars, including 3/5 of its cars with CD players. if 3/4 of its cars have CD players, what percentage of the cars that were not rented had CD players ?

a. 10%
b. 35%
c. 45 %
d. 66.7%
e. 90%
One day a car rental agency rented 2/3 of its cars
2/3 of 120 = 80, so 80 cars were rented.
This also means that 40 cars were NOT rented.

3/4 of its cars have CD players
3/4 of 120 = 90, so 90 cars have CD players.

The agency rented 3/5 of its cars with CD players.
From above, we know that 90 cars have CD players.
So, 3/5 of those 90 cars were rented.
3/5 of 90 = 54, so 54 cars with CD players were RENTED.
This also means that 36 with CD players were NOT rented.


What percentage of the cars that were not rented had CD players?
We know that 40 cars we NOT rented.
We also know that 36 with CD players were NOT rented.
So, 36 of the 40 unrented cars have CD player.
36/40 = [spoiler]90%[/spoiler] = E

Cheers,
Brent
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by theCodeToGMAT » Fri Sep 27, 2013 11:22 am
Malolo355 wrote:I don't get it...
I go over and over again that problem and I keep having the same result..35% (B)
Is there any other solution other than assuming that we have 60 cars?
Can someone pls enlighten me?
Here's my calculation.. sorry i assumed 120.. so all the figures for 60 would be half of 120.
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by Brent@GMATPrepNow » Fri Sep 27, 2013 11:24 am
Malolo355 wrote:I don't get it...
I go over and over again that problem and I keep having the same result..35% (B)
Is there any other solution other than assuming that we have 60 cars?
Can someone pls enlighten me?
We can also solve the question algebraically, but it's NOT PRETTY (which is why plugging in nice numbers is the preferred approach).
One day a car rental agency rented 2/3 of its cars, including 3/5 of its cars with CD players. if 3/4 of its cars have CD players, what percentage of the cars that were not rented had CD players ?

a. 10%
b. 35%
c. 45 %
d. 66.7%
e. 90%
Let x = total number of cars

One day a car rental agency rented 2/3 of its cars
So, 1/3 of the care we NOT RENTED
1/3 of x = x/3, so x/3 cars were NOT rented.

3/4 of its cars have CD players
3/4 of x = 3x/4, so 3x/4 cars have CD players.

The agency rented 3/5 of its cars with CD players.
From above, we know that 3x/4 cars have CD players.
3/5 of those 3x/4 cars were rented.
This means that 2/5 of those 3x/4 cars were NOT rented.
(2/5)(3x/4) = 3x/10. So, 3x/10 with CD players were NOT rented.


What percentage of the cars that were not rented had CD players?
We know that x/3 cars we NOT rented.
We also know that 3x/10 with CD players were NOT rented.
So, 3x/10 of the x/3 unrented cars have CD player.
[3x/10]/[x/3] =
= [3/10]/[1/3]
= 9/10
= [spoiler]90%[/spoiler]
= E

Cheers,
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by fourteenstix » Fri Sep 27, 2013 11:26 am
Don't get hung up on the 60. After a brief look at the answer choices, you don't need to be precise here. My first move was to pick 100. The other approaches actually end up easier, but here's another look since you're still puzzled.

Image

After picking 100 for the total, you can calculate all the numbers in white based on information in the stimulus. Again, since we don't need to be precise, 66 is close enough to 2/3rds of 100

From there, you are able to populate all the fields in yellow (again, 34 is close enough to 1/3 of 100). Now that we have our double matrix fully populated, let's double check that we're answering the right question. I think this is where you've been getting caught up.

We want "not rented cars with CD players" as a percentage of "total not rented cars". Referring to the table, that's 30 / 34. Hopefully it's clear that 30 / 34 (or 15/17) is closest to 90%.

Again, seeing the other approaches, picking 60 comes out much cleaner and I would advise that approach for this problem. Just make sure you're answering the right question and you should be fine!

Cheers
Malolo355 wrote:I don't get it...
I go over and over again that problem and I keep having the same result..35% (B)
Is there any other solution other than assuming that we have 60 cars?
Can someone pls enlighten me?

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by GMATGuruNY » Sat Sep 28, 2013 4:10 am
charmaine wrote:one day a car rental agency rented 2/3 of its cars, including 3/5 of its cars with CD players. if 3/4 of its cars have CD players, what percentage of the cars that were not rented had CD players ?

a. 10%
b. 35%
c. 45 %
d. 66.7%
e. 90%
This is an EITHER/OR group problem.
Every car EITHER was rented OR was not.
Every car EITHER has a CD player OR does not.
For an EITHER/OR group problem, we can use a GROUP GRID (also known as a double-matrix) to organize the data.

Let R = rented, NR = not rented, CD = CD player, NCD = no CD player.
In the grids below, the entries in any given row or column must add up to the TOTAL of that row or column.

Let the total = the LCM of the denominators in the problem (3, 4, 5) = 60:
Image

Now complete the grid step by step.
Calculate the EASIEST values first.

Rented 2/3 of its cars.
3/4 of its cars have CD players.

Image

Rented 3/5 of its cars with CD players.
Thus, of the 45 cars with CD players, the number rented = (3/5) * 45 = 27, yielding the following grid:
Image

Thus:
(not rented with CD players)/(total not rented) = 18/20 * 100 = 90%.

The correct answer is E.
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by Malolo355 » Tue Oct 01, 2013 2:40 am
Thanks everyone! I found the cross tabulation table really helpful..
It seems that i couldn't have the result simply beacuse i didn't do (notRented with Cd / 1:3 total cars)
Thanks again!