[GMAT math practice question]
What is the minimum distance between the point (3,4) and points on the circle x^2+y^2=1?
A. 1
B. 2
C. 3
D. 4
E. 5
What is the minimum distance between the point (3,4) and po
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- Max@Math Revolution
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Hi Max@Math Revolution,
I think that this question can be solved as follow,
We need to find the distance between (3, 4) and (0, 0), this will be 5.
Then, the radius of the circle is 1, hence the distance between (3, 4) and points of the circle is 5 - 1 = 4. Option D.
Regards!
I think that this question can be solved as follow,
We need to find the distance between (3, 4) and (0, 0), this will be 5.
Then, the radius of the circle is 1, hence the distance between (3, 4) and points of the circle is 5 - 1 = 4. Option D.
Regards!
- Max@Math Revolution
- Elite Legendary Member
- Posts: 3991
- Joined: Fri Jul 24, 2015 2:28 am
- Location: Las Vegas, USA
- Thanked: 19 times
- Followed by:37 members
=>
Since the distance between (0,0) the center of the circle x^2+y^2=1 and (3,4) is 5, and the radius of the circle is 1, the minimum distance between a point on the circle and (3,4) is 5 - 1 = 4.
Therefore, D is the answer.
Answer: D
Since the distance between (0,0) the center of the circle x^2+y^2=1 and (3,4) is 5, and the radius of the circle is 1, the minimum distance between a point on the circle and (3,4) is 5 - 1 = 4.
Therefore, D is the answer.
Answer: D
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[Free] Full on-demand course (7 days) - 100 hours of video lessons, 490 lesson topics, and 2,000 questions.
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