Cost of swimming

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Cost of swimming

by sandeep_chhabra » Thu May 15, 2008 2:55 am
I solved this question like this:

D + (2/3)DG
=> (3D + 2DG)/3 -----(taking LCM)
=> (D(3+2G))/2 -----(taking D common)

according to me answer should be choice D but somehow it is B. Dont know where am i going wrong :(
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by ksh » Thu May 15, 2008 3:06 am
cost of swimming = d+2/3*d*(g-1)

=(3d+2dg-2d)/3 =d(2g+1)/3