Dannetta has a jar containing red pens and black pens. If she selects one pen at random from the jar, what is the probability that the pen will be red?
If Dannetta removes 9 black pens from the jar, there will be an equal number of red and black pens remaining in the jar.
If Dannetta removes 1/6 of the black pens, 3/7 of the pens remaining in the jar will be red.
DS - Probability tough one (atleast consumes time...)
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- karthikpandian19
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On the contrary, this question should take very little time.karthikpandian19 wrote:Dannetta has a jar containing red pens and black pens. If she selects one pen at random from the jar, what is the probability that the pen will be red?
If Dannetta removes 9 black pens from the jar, there will be an equal number of red and black pens remaining in the jar.
If Dannetta removes 1/6 of the black pens, 3/7 of the pens remaining in the jar will be red.
To determine P(red), we need to know what fraction of the pens are red (or, alternatively, what fraction are black).
Statement 1: If Dannetta removes 9 black pens from the jar, there will be an equal number of red and black pens remaining in the jar.
Different fractions are possible.
If 1 black pen and 1 red pen remain, then prior to the removal of the 9 black pens, B=10 and R=1, implying that P(R) = 1/11.
If 10 black pens and 10 red pens remain, then prior to the removal of the 9 black pens, B=19 and R=10, implying that P(R) = 10/29.
INSUFFICIENT.
Statement 2: If Dannetta removes 1/6 of the black pens, 3/7 of the pens remaining in the jar will be red.
In other words, the remaining 5/6 of the black pens will constitute 4/7 of the remaining pens in the jar:
This information is sufficient to determine what fraction of the pens are black (and thus what fraction are red).
SUFFICIENT.
The correct answer is B.
Here's the math for statement 2:
The remaining 5/6 of the black pens will constitute 4/7 of the remaining pens in the jar.
Let B = black and T = total.
(5/6)B = (4/7)(T - (1/6)B)
(5/6)B = (4/7)T - (4/42)B
(39/42)B = (4/7)T
B = (24/39)T.
Thus, if T=39, then B=24 and R=15.
P(R) = 15/39 = 5/13.
Please note that WE SHOULDN'T DO THIS MATH WHEN WE TAKE THE ACTUAL TEST.
As soon as we realize that statement 2 is sufficient to determine what fraction of the marbles are black, we should pick answer choice B and move on.
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- karthikpandian19
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OA is B
GMATGuruNY wrote:On the contrary, this question should take very little time.karthikpandian19 wrote:Dannetta has a jar containing red pens and black pens. If she selects one pen at random from the jar, what is the probability that the pen will be red?
If Dannetta removes 9 black pens from the jar, there will be an equal number of red and black pens remaining in the jar.
If Dannetta removes 1/6 of the black pens, 3/7 of the pens remaining in the jar will be red.
To determine P(red), we need to know what fraction of the pens are red (or, alternatively, what fraction are black).
Statement 1: If Dannetta removes 9 black pens from the jar, there will be an equal number of red and black pens remaining in the jar.
Different fractions are possible.
If 1 black pen and 1 red pen remain, then prior to the removal of the 9 black pens, B=10 and R=1, implying that P(R) = 1/11.
If 10 black pens and 10 red pens remain, then prior to the removal of the 9 black pens, B=19 and R=10, implying that P(R) = 10/29.
INSUFFICIENT.
Statement 2: If Dannetta removes 1/6 of the black pens, 3/7 of the pens remaining in the jar will be red.
In other words, the remaining 5/6 of the black pens will constitute 4/7 of the remaining pens in the jar:
This information is sufficient to determine what fraction of the pens are black (and thus what fraction are red).
SUFFICIENT.
The correct answer is B.
Here's the math for statement 2:
The remaining 5/6 of the black pens will constitute 4/7 of the remaining pens in the jar.
Let B = black and T = total.
(5/6)B = (4/7)(T - (1/6)B)
(5/6)B = (4/7)T - (4/42)B
(39/42)B = (4/7)T
B = (24/39)T.
Thus, if T=39, then B=24 and R=15.
P(R) = 15/39 = 5/13.
Please note that WE SHOULDN'T DO THIS MATH WHEN WE TAKE THE ACTUAL TEST.
As soon as we realize that statement 2 is sufficient to determine what fraction of the marbles are black, we should pick answer choice B and move on.
Regards,
Karthik
The source of the questions that i post from JUNE 2013 is from KNEWTON
---If you find my post useful, click "Thank" ---
---Never stop until cracking GMAT---
Karthik
The source of the questions that i post from JUNE 2013 is from KNEWTON
---If you find my post useful, click "Thank" ---
---Never stop until cracking GMAT---