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srikanthb.69
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x1+x2+140+x3+x4 = 124*5 =620
consider min for x3 and x4 for x1 to be max. i.e 140
so x1+x2+ 3*140= 620 =>x1+x2 = 620-420 = 200
and x1 can be eq or less than x2 so it is max when it is eq to x2
hence 2x1 = 200 and x1 = 100.
consider min for x3 and x4 for x1 to be max. i.e 140
so x1+x2+ 3*140= 620 =>x1+x2 = 620-420 = 200
and x1 can be eq or less than x2 so it is max when it is eq to x2
hence 2x1 = 200 and x1 = 100.
