Help Needed
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Last edited by yogeshsheth on Wed Aug 13, 2008 8:51 am, edited 1 time in total.
If you look at statement 2, you already know that you can figure out the problem because every variable is solved for you. This leaves answer choices B and D
For statement 1, you can just plug in numbers and you should be able to solve it.
Answer is D.
For statement 1, you can just plug in numbers and you should be able to solve it.
Answer is D.
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Is x – y > r – s?
(1) x > r and y < s
x-y > r-s ??
or
x-r > y-s
x-r is +ve number from 1
y-s is -ve number from 1
so x-y is greater then y-s
(1) x > r and y < s
x-y > r-s ??
or
x-r > y-s
x-r is +ve number from 1
y-s is -ve number from 1
so x-y is greater then y-s
- mukul
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Guyz!!
I think everyone missed the point here!! yogesh asks for a sytematic approach...plugging is gud but as yogesh rightly points out that u may miss some cases.
Can anyone please advice on the best way to tackle such questions
eg14. Is x – y > r – s?
(1) x > r and y < s?
(2) y = 2, s = 3, r = 5, and x = 6.
I wud try to giv a systematic approach here..
Given: from 1. x > r and y < s
i wud make one expression +ve and one -ve. then i can confidently say that +ve > -ve
so x-r>0 and y-s<0 from whats given...
now simple...x-r is +ve and y-s is -ve
so x-r>y-s ....true!!
thats it...this can be applied to all such questions...finally it boils down to getin the expression in the apt form.
hope it helps!!
I think everyone missed the point here!! yogesh asks for a sytematic approach...plugging is gud but as yogesh rightly points out that u may miss some cases.
Can anyone please advice on the best way to tackle such questions
eg14. Is x – y > r – s?
(1) x > r and y < s?
(2) y = 2, s = 3, r = 5, and x = 6.
I wud try to giv a systematic approach here..
Given: from 1. x > r and y < s
i wud make one expression +ve and one -ve. then i can confidently say that +ve > -ve
so x-r>0 and y-s<0 from whats given...
now simple...x-r is +ve and y-s is -ve
so x-r>y-s ....true!!
thats it...this can be applied to all such questions...finally it boils down to getin the expression in the apt form.
hope it helps!!
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